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Author: 2610Shubham

query_analysis.sql

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+# Employee Demographics & Department Overview:
+
+
+-- 1. Total Number of Employees in Each Department
+SELECT 
+    department_name,
+    COUNT(emp_id) AS 'Total Employee Cnt per Department'
+FROM
+    employees
+        INNER JOIN
+    departments ON employees.department_id = departments.dep_id
+GROUP BY department_name;
+
+-- 2. Department with the Most Employees
+SELECT 
+    d.department_name, COUNT(e.emp_id) AS Employees_cnt
+FROM
+    departments d
+        INNER JOIN
+    employees e ON d.dep_id = e.department_id
+GROUP BY department_name
+ORDER BY Employees_cnt DESC
+LIMIT 1;
+    
+-- 3. Employees Who Have Worked for More Than 5 Years
+SELECT 
+    emp_id,
+    first_name,
+    last_name,
+    joining_date,
+    ROUND(DATEDIFF(CURDATE(), joining_date) / 365,
+            0) AS Years_Of_Service
+FROM
+    employees
+WHERE
+    DATEDIFF(CURDATE(), JOINING_DATE) / 365 > 5
+ORDER BY Years_Of_Service DESC;
+    
+-- 4. Department with the Highest Average Performance Score
+SELECT 
+    d.department_name,
+    ROUND(AVG(ep.performance_score), 1) AS Avg_Performance
+FROM
+    departments d
+        INNER JOIN
+    employees e ON d.dep_id = e.department_id
+        INNER JOIN
+    employee_performance ep ON e.emp_id = ep.employee_id
+GROUP BY d.department_name
+ORDER BY Avg_Performance DESC
+LIMIT 1;
+    
+
+# Salary & Compensation:
+-- 5. Average Salary by Department
+SELECT 
+    department_name, ROUND(AVG(salary), 2) AS 'Avg Salary'
+FROM
+    departments
+        INNER JOIN
+    employees ON employees.department_id = departments.dep_id
+GROUP BY department_name
+ORDER BY department_name;
+
+-- 6. Highest and Lowest Salary in Each Department
+SELECT 
+    department_name,
+    MAX(salary) AS 'Highest Salary',
+    MIN(salary) AS 'Lowest Salary'
+FROM
+    employees
+        INNER JOIN
+    departments ON employees.department_id = departments.dep_id
+GROUP BY department_name;
+
+-- 7. Employees with Salary Greater than the Department Average
+SELECT 
+    e.emp_id,
+    e.first_name,
+    e.last_name,
+    e.salary,
+    d.department_name
+FROM
+    employees e
+        INNER JOIN
+    departments d ON e.department_id = d.dep_id
+WHERE
+    e.salary > (SELECT 
+            AVG(salary)
+        FROM
+            employees
+        WHERE
+            e.department_id = d.dep_id
+            );
+            
+-- 8. Total Salary Expenditure by Department
+SELECT 
+    d.department_name, SUM(e.salary) AS Total_salary
+FROM
+    departments d
+        INNER JOIN
+    employees e ON d.dep_id = e.department_id
+GROUP BY d.department_name
+ORDER BY Total_salary DESC;
+
+
+# Employee Performance & Engagement:
+
+-- 9. Employees with a Performance Score of 5
+SELECT 
+    e.emp_id, e.first_name, e.last_name, ep.Performance_Score
+FROM
+    employees e
+        JOIN
+    employee_Performance ep ON e.emp_id = ep.employee_ID
+WHERE
+    ep.Performance_Score = 5;
+    
+-- 10. Average Performance Score by Department
+SELECT 
+    d.department_name,
+    ROUND(AVG(ep.performance_score), 1) AS avg_performance_score
+FROM
+    departments d
+        INNER JOIN
+    employees e ON d.dep_id = e.department_id
+        INNER JOIN
+    employee_performance ep ON e.emp_id = ep.employee_id
+GROUP BY d.department_name
+ORDER BY avg_performance_score DESC;
+    
+-- 11. Employees with the Most Leaves Taken
+SELECT 
+    e.emp_id,
+    e.first_name,
+    e.last_name,
+    COUNT(el.leave_id) AS Total_Leaves
+FROM
+    employees e
+        INNER JOIN
+    employee_leave el ON e.emp_id = el.employee_id
+GROUP BY e.emp_id , e.first_name , e.last_name
+ORDER BY Total_Leaves DESC
+LIMIT 1;
+
+-- 12. Employees with No Leaves Taken
+SELECT 
+    e.emp_id, e.first_name, e.last_name
+FROM
+    employees e
+        LEFT JOIN
+    employee_leave el ON e.emp_id = el.employee_id
+WHERE
+    el.employee_id IS NULL;
+
+
+# Employee Management:
+-- 13. List of Employees with Their Manager's Name
+SELECT 
+    e.emp_id,
+    e.first_name AS employee_first_name,
+    e.last_name AS employee_last_name,
+    m.first_name AS manager_first_name,
+    m.last_name AS manager_last_name
+FROM
+    departments d
+        INNER JOIN
+    employees e ON d.dep_id = e.department_id
+        LEFT JOIN
+    employees m ON d.manager_id = m.emp_id;
+
+
+
+
+    

schema_and_data.sql

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+-- Drop the database if it exists
+DROP DATABASE IF EXISTS employeedb;
+
+-- Create the database
+CREATE DATABASE employeedb;
+
+-- Switch to the created database
+USE employeedb;
+
+
+CREATE TABLE departments (
+    dep_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
+    department_name VARCHAR(100) NOT NULL,
+    manager_id INT,  -- Manager will be added as a foreign key later
+    location VARCHAR(100)
+);
+
+CREATE TABLE employees (
+    emp_id INT PRIMARY KEY AUTO_INCREMENT,
+    first_name VARCHAR(100) NOT NULL,
+    last_name VARCHAR(100) NOT NULL,
+    date_of_birth DATE NOT NULL,
+    gender VARCHAR(10),
+    joining_date DATE NOT NULL,
+    department_id INT,  -- Links to departments table
+    salary DECIMAL(10 , 2 ) NOT NULL,
+    job_title VARCHAR(100),
+    location VARCHAR(100),
+    CONSTRAINT fk_department_id FOREIGN KEY (department_id)
+        REFERENCES departments (dep_id)
+);
+
+-- Once both departments and employees tables are created, add the foreign key for manager_id:
+ALTER TABLE departments 
+ADD CONSTRAINT fk_manager_id FOREIGN KEY (manager_id)
+REFERENCES employees (emp_id);
+
+CREATE TABLE salaries (
+    salary_id INT PRIMARY KEY AUTO_INCREMENT,
+    employee_id INT,  -- Links to employees table
+    salary DECIMAL(10 , 2 ) NOT NULL,
+    effective_date DATE NOT NULL,
+    CONSTRAINT fk_employee_id FOREIGN KEY (employee_id)
+        REFERENCES employees (emp_id)
+);
+
+
+CREATE TABLE employee_performance (
+    performance_id INT PRIMARY KEY AUTO_INCREMENT,
+    employee_id INT NOT NULL,  -- Links to employees table
+    performance_score INT,
+    review_date DATE NOT NULL,
+    manager_id INT NOT NULL,  -- Links to employees table
+    CONSTRAINT score_between_1_and_5 CHECK (performance_score BETWEEN 1 AND 5),
+    CONSTRAINT fk_emp_performance_manager_id FOREIGN KEY (manager_id)
+        REFERENCES employees (emp_id),
+    CONSTRAINT fk_emp_performance_employee_id FOREIGN KEY (employee_id)
+        REFERENCES employees (emp_id)
+);
+
+
+
+CREATE TABLE employee_leave (
+    leave_id INT PRIMARY KEY AUTO_INCREMENT,
+    employee_id INT NOT NULL,  -- Links to employees table
+    leave_type VARCHAR(50) NOT NULL,
+    start_date DATE NOT NULL,
+    end_date DATE NOT NULL,
+    CONSTRAINT fk_emp_leave_employee_id FOREIGN KEY (employee_id)
+        REFERENCES employees (emp_id)
+);
+
+
+INSERT INTO Departments (dep_id, department_name, manager_id, location)
+VALUES 
+(1, 'Human Resources', NULL, 'New York'),
+(2, 'Engineering', NULL, 'San Francisco'),
+(3, 'Sales', NULL, 'Chicago'),
+(4, 'Marketing', NULL, 'Boston'),
+(5, 'Finance', NULL, 'Los Angeles');
+
+INSERT INTO Employees (emp_id, first_name, last_name, date_of_birth, gender, joining_date, department_id, salary, job_title, location)
+VALUES 
+(1, 'Alice', 'Smith', '1985-02-14', 'Female', '2010-06-15', 2, 95000.00, 'Senior Engineer', 'San Francisco'),
+(2, 'Bob', 'Johnson', '1990-08-22', 'Male', '2015-09-01', 2, 85000.00, 'Software Engineer', 'San Francisco'),
+(3, 'Charlie', 'Brown', '1980-12-12', 'Male', '2005-01-20', 3, 75000.00, 'Sales Manager', 'Chicago'),
+(4, 'Diana', 'Williams', '1992-03-28', 'Female', '2018-07-19', 1, 65000.00, 'HR Specialist', 'New York'),
+(5, 'Evan', 'Taylor', '1987-11-10', 'Male', '2012-10-05', 4, 72000.00, 'Marketing Analyst', 'Boston'),
+(6, 'Grace', 'Lee', '1995-06-05', 'Female', '2021-01-12', 5, 78000.00, 'Financial Analyst', 'Los Angeles'),
+(7, 'John', 'Doe', '1989-03-22', 'Male', '2017-05-23', 4, 70000.00, 'Marketing Manager', 'Boston');
+
+
+-- Setting the manager_id for each department
+UPDATE Departments
+SET manager_id = 1
+WHERE dep_id = 2;  -- Engineering department manager is Alice Smith
+
+UPDATE Departments
+SET manager_id = 3
+WHERE dep_id = 3;  -- Sales department manager is Charlie Brown
+
+UPDATE Departments
+SET manager_id = 4
+WHERE dep_id = 1;  -- HR department manager is Diana Williams
+
+UPDATE Departments
+SET manager_id = 5
+WHERE dep_id = 4;  -- Marketing department manager is Evan Taylor
+
+
+
+INSERT INTO Salaries (salary_id, employee_id, salary, effective_date)
+VALUES 
+(1, 1, 95000.00, '2020-01-01'),
+(2, 1, 90000.00, '2018-01-01'),
+(3, 2, 85000.00, '2021-06-01'),
+(4, 3, 75000.00, '2019-09-01'),
+(5, 4, 65000.00, '2022-03-01'),
+(6, 5, 72000.00, '2020-10-01'),
+(7, 6, 78000.00, '2021-01-12');
+
+
+INSERT INTO Employee_Performance (performance_id, employee_id, performance_score, review_date, manager_id)
+VALUES 
+(1, 1, 5, '2023-06-01', 1),
+(2, 2, 4, '2023-06-01', 1),
+(3, 3, 3, '2022-12-15', 3),
+(4, 4, 4, '2023-03-20', 4),
+(5, 5, 5, '2023-05-10', 5),
+(6, 6, 4, '2023-04-15', 5),
+(7, 7, 3, '2023-07-01', 4);
+
+
+INSERT INTO Employee_Leave (leave_id, employee_id, leave_type, start_date, end_date)
+VALUES 
+(1, 1, 'Vacation', '2023-08-01', '2023-08-15'),
+(2, 2, 'Sick Leave', '2023-09-10', '2023-09-12'),
+(3, 3, 'Vacation', '2023-07-05', '2023-07-15'),
+(4, 4, 'Maternity Leave', '2023-01-10', '2023-03-10'),
+(5, 5, 'Sick Leave', '2023-06-20', '2023-06-22'),
+(6, 6, 'Vacation', '2023-05-01', '2023-05-10'),
+(7, 7, 'Personal Leave', '2023-09-01', '2023-09-05');
+
+
+
+
+
+