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Copy path032_Add_Two_Numbers
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37 lines (32 loc) · 1.03 KB
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You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
C++
using namespace std;
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode* head = new ListNode(0);
ListNode* curr = head;
int carry = 0;
while(l1 != NULL || l2 != NULL || carry!=0){
int x = 0, y = 0;
if(l1){
x = l1->val;
}
if(l2){
y = l2->val;
}
int sum = carry+x+y;
carry = sum/10;
curr->next = new ListNode(sum % 10);
curr = curr->next;
if(l1){
l1 = l1->next;
}
if(l2){
l2 = l2->next;
}
}
return head->next;
}
};