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README.md

Minimum Index Sum of Two Lists

Runtime: 10 ms (Top 81.82%) | Memory: 2.40 MB (Top 27.27%)

Jan 25, 2024

a5fdf66 · Jan 25, 2024

Name	Name	Last commit message	Last commit date
parent directory ..
Minimum Index Sum of Two Lists.cpp	Minimum Index Sum of Two Lists.cpp	Runtime: 70 ms (Top 74.0%) \| Memory: 37.30 MB (Top 38.8%)	Jan 6, 2024
Minimum Index Sum of Two Lists.java	Minimum Index Sum of Two Lists.java	Runtime: 7 ms (Top 93.08%) \| Memory: 45.40 MB (Top 19.13%)	Jan 15, 2024
Minimum Index Sum of Two Lists.js	Minimum Index Sum of Two Lists.js	Runtime: 170 ms (Top 33.33%) \| Memory: 48.8 MB (Top 57.06%)	Aug 28, 2022
Minimum Index Sum of Two Lists.py	Minimum Index Sum of Two Lists.py	Updated Project format	Aug 17, 2022
Minimum Index Sum of Two Lists.rs	Minimum Index Sum of Two Lists.rs	Runtime: 10 ms (Top 81.82%) \| Memory: 2.40 MB (Top 27.27%)	Jan 25, 2024
README.md	README.md	Added problem description	Aug 21, 2022
info.json	info.json	Updated Project format	Aug 17, 2022

README.md

599. Minimum Index Sum of Two Lists

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

Example 1:

Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["Piatti","The Grill at Torrey Pines","Hungry Hunter Steakhouse","Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".

Example 2:

Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KFC","Shogun","Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).

Constraints:

1 <= list1.length, list2.length <= 1000
1 <= list1[i].length, list2[i].length <= 30
list1[i] and list2[i] consist of spaces ' ' and English letters.
All the stings of list1 are unique.
All the stings of list2 are unique.

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