Step-By-Step Directions From a Binary Tree Node to Another.java

class Solution {
    
    private boolean DFS(TreeNode currNode, StringBuilder path, int destVal) {
        if(currNode == null) return false;
        if(currNode.val == destVal) return true;
        if(DFS(currNode.left, path, destVal)) path.append("L");
        else if(DFS(currNode.right, path, destVal)) path.append("R");
        return path.length() > 0;
    }
    
    public String getDirections(TreeNode root, int startValue, int destValue) {
        StringBuilder startToRoot = new StringBuilder();
        StringBuilder endToRoot = new StringBuilder();
        
        DFS(root, startToRoot, startValue);
        DFS(root, endToRoot, destValue);
        
        int i = startToRoot.length(), j = endToRoot.length();
        int cnt = 0;
        while(i > 0 && j > 0 && startToRoot.charAt(i-1) == endToRoot.charAt(j-1)) {
            cnt++; i--; j--;
        }
        
        String sPath = "U".repeat(startToRoot.length() - cnt);
        String ePath = endToRoot.reverse().toString().substring(cnt, endToRoot.length());
        
        return sPath + ePath;
    }
}