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LeetCode 面试题 08.08. 有重复字符串的排列组合 #10

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Chocolate1999 opened this issue Sep 13, 2020 · 0 comments
Open

LeetCode 面试题 08.08. 有重复字符串的排列组合 #10

Chocolate1999 opened this issue Sep 13, 2020 · 0 comments
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递归与回溯 LeetCode 递归与回溯专栏

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@Chocolate1999
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仰望星空的人,不应该被嘲笑

题目描述

有重复字符串的排列组合。编写一种方法,计算某字符串的所有排列组合。

示例1:

 输入:S = "qqe"
 输出:["eqq","qeq","qqe"]

示例2:

 输入:S = "ab"
 输出:["ab", "ba"]

提示:

字符都是英文字母。
字符串长度在[1, 9]之间。

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/permutation-ii-lcci
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

解题思路

全排列,直接用回溯法即可,数据量比较小,暴力完事~

var permutation = function (S) {
  let res = new Set()
  let vis = []
  let dfs = (t) => {
    if (t.length === S.length) return res.add(t)
    for (let i = 0; i < S.length; i++) {
      if (vis[i]) continue
      vis[i] = true
      dfs(t + S[i])
      vis[i] = false
    }
  }
  dfs('')
  return [...res]
}

最后

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@Chocolate1999 Chocolate1999 added the 递归与回溯 LeetCode 递归与回溯专栏 label Sep 13, 2020
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