[Query] Is there a way to generate all resources from an existing database?

[skills-up]

Hi,

Is there a way to generate all the resources from an existing database?

I know we can generate resources pertaining to individual tables using:
php artisan resource-file:from-database [model-name]

What I wish to know is if there is any command like:
php artisan resource-file:from-database --all-tables
to generate resources for all the tables in the database with a single command?

This will be really helpful for generating one click demos/applications from a schema, without the need to write a separate script to iterate through the database, and generating corresponding commands in the shell.

Thanks,
Gaurav

[MikeAlhayek]

It’s been a while since I used it, but please tryphp artisan create:mapped-resources.

The mapped-resources command is designed to allow you to create multiple resources all specified at once.

If you created resources using this package, most likely you already have resources/laravel-code-generator/sources/resources_map.json created. Update that file directly by adding resources to it. Once you add a new entry for each resource you want to create, call php artisan create:mapped-resources and all the resources should get created for you.

This command could be improved in the future to allow you to generate resource for every table on a given database. But in most cases, you’ll never want a CRUD for every table which is why the mapped-resource command allow you to only add what you really need.

You may also want to review the documentation on how to correctly modify the map file https://crestapps.com/laravel-code-generator/docs/2.2 The documentation has two related sections, once talks about the command and the second talk about the file’s format and what commands available there

I hope this helps.

PS: kindly use stackoverflow.com for question where github is for bugs or new future requests.

[dbilovd]

@skills-up this is what I've used.

First, run SHOW TABLES; to get a list of all tables in your DB
Then map each table name to its model name in an array. Loop through the array and run the resource-file:from-database with each set of values.

$models = [ "tableName" => "ModelName" ];

array_walk($models, function ($model, $table) {
  $this->call('resource-file:from-database', [
    'model-name'    => $model,
    '--table-name'  => $table
  ]);
});

This will create all the necessary resource files and you can carry on from there.

NB: You can run the above code within Tinker.

[dbilovd]

@CrestApps what do you think about the approach I suggested here #120 (comment) ?

I can submit a PR to add it as an option to the package.

[MikeAlhayek]

@dbilovd the problem with that approach is SHOW TABLES is mysql specific command. It won't work with other database servers.

I suggest creating a new command called resource-file:from-database-all with no required parameters. Then I would clone the resource-file:from-database command but eliminate the model-name as parameter and --database-name, --resource-filename as options.

That code in the ResourceFileFromdatabaseCommand.php has a method called getParser() which gives you parser for the connected-to database. The parser should be modified to expose a method that would return an array of all tables found on the database. To do that, you'll need to add a new abstract method on the ParserBase.php class abstract protected function getTableNames();

Then in the MySqlParser you'll implement the getTableNames() method which returns the result of SHOW TABLES command.

If you do that, please submit a PR request.

[MikeAlhayek]

@dbilovd you can even make the getModelName($tableName) public and then call $parser->getModelName("table-name") within your new command to get the model name following the default naming convention.