Merge pull request #1572 from HoonDongKang/main

[HoonDongKang] Week 11 Solutions

Author: HoonDongKang

binary-tree-maximum-path-sum/HoonDongKang.ts

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+/**
+ * [Problem]: [124 Binary Tree Maximum Path Sum
+ * (https://leetcode.com/problems/binary-tree-maximum-path-sum/description/)
+ */
+/**
+ * Definition for a binary tree node.
+ * class TreeNode {
+ *     val: number
+ *     left: TreeNode | null
+ *     right: TreeNode | null
+ *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
+ *         this.val = (val===undefined ? 0 : val)
+ *         this.left = (left===undefined ? null : left)
+ *         this.right = (right===undefined ? null : right)
+ *     }
+ * }
+ */
+
+//시간복잡도 O(n)
+//공간복잡도 O(h)
+function maxPathSum(root: TreeNode | null): number {
+    if (!root) return 0;
+    let result = root.val;
+
+    function dfs(node: TreeNode | null) {
+        if (!node) return 0;
+
+        let leftMax = Math.max(dfs(node.left), 0);
+        let rightMax = Math.max(dfs(node.right), 0);
+
+        result = Math.max(node.val + leftMax + rightMax, result);
+
+        return node.val + Math.max(leftMax, rightMax);
+    }
+
+    dfs(root);
+    return result;
+}

graph-valid-tree/HoonDongKang.ts

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+/**
+ * [Problem]: [178] Graph Valid Tree
+ * (https://www.lintcode.com/problem/178/)
+ */
+
+export class Solution {
+    /**
+     * @param n: An integer
+     * @param edges: a list of undirected edges
+     * @return: true if it's a valid tree, or false
+     */
+    //시간복잡도 O(n+e)
+    //공간복잡도 O(n+e)
+    validTree(n: number, edges: number[][]): boolean {
+        const graph: number[][] = Array.from({ length: n }, () => []);
+        for (const [a, b] of edges) {
+            graph[a].push(b);
+            graph[b].push(a);
+        }
+
+        const visited = new Set<number>();
+
+        function hasCycle(node: number, prev: number): boolean {
+            if (visited.has(node)) return true;
+            visited.add(node);
+
+            for (const neighbor of graph[node]) {
+                if (neighbor === prev) continue;
+                if (hasCycle(neighbor, node)) return true;
+            }
+            return false;
+        }
+
+        if (hasCycle(0, -1)) return false;
+
+        return visited.size === n;
+    }
+
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    validTree2(n: number, edges: number[][]): boolean {
+        if (edges.length !== n - 1) return false;
+
+        const graph: number[][] = Array.from({ length: n }, () => []);
+        for (const [a, b] of edges) {
+            graph[a].push(b);
+            graph[b].push(a);
+        }
+
+        const visited = new Set<number>();
+
+        function dfs(node: number) {
+            visited.add(node);
+            for (const neighbor of graph[node]) {
+                if (!visited.has(neighbor)) {
+                    dfs(neighbor);
+                }
+            }
+        }
+
+        dfs(0);
+
+        return visited.size === n;
+    }
+}

merge-intervals/HoonDongKang.ts

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+/**
+ * [Problem]: [56] Merge Intervals
+ * (https://leetcode.com/problems/merge-intervals/description/)
+ */
+function merge(intervals: number[][]): number[][] {
+    //시간복잡도 O(n^2)
+    //공간복잡도 O(n)
+    function bruteForceFunc(intervals: number[][]): number[][] {
+        const result: number[][] = [];
+        const visited = new Set<number>();
+
+        for (let i = 0; i < intervals.length; i++) {
+            if (visited.has(i)) continue;
+            visited.add(i);
+
+            while (true) {
+                let hasMerged = false;
+                for (let j = 0; j < intervals.length; j++) {
+                    if (visited.has(j)) continue;
+
+                    const [curA, curB] = intervals[i];
+                    const [nextA, nextB] = intervals[j];
+
+                    if (curA <= nextB && nextA <= curB) {
+                        visited.add(j);
+                        intervals[i] = [Math.min(curA, nextA), Math.max(curB, nextB)];
+
+                        hasMerged = true;
+                    }
+                }
+                if (!hasMerged) break;
+            }
+            result.push(intervals[i]);
+        }
+        return result;
+    }
+
+    //시간복잡도 O(nlog n)
+    //공간복잡도 O(n)
+    function sortFunc(intervals: number[][]): number[][] {
+        if (!intervals.length) return intervals;
+        intervals.sort((a, b) => a[0] - b[0]);
+
+        const result: number[][] = [intervals[0]];
+        for (let i = 0; i < intervals.length; i++) {
+            const prev = result[result.length - 1];
+            const cur = intervals[i];
+
+            if (cur[0] <= prev[1]) {
+                prev[1] = Math.max(prev[1], cur[1]);
+            } else {
+                result.push(cur);
+            }
+        }
+
+        return result;
+    }
+}

missing-number/HoonDongKang.ts

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+/**
+ * [Problem]: [268] Missing Number
+ * (https://leetcode.com/problems/missing-number/description/)
+ */
+function missingNumber(nums: number[]): number {
+    //시간복잡도 O(n^2)
+    //공간복잡도 O(1)
+    function loopFunc(nums: number[]): number {
+        let num = 0;
+        while (true) {
+            if (!nums.includes(num)) break;
+            num++;
+        }
+
+        return num;
+    }
+    //시간복잡도 O(n)
+    //공간복잡도 O(1)
+    function sumFunc(nums: number[]): number {
+        const n = nums.length;
+        const sum = nums.reduce((acc, cur) => (acc += cur), 0);
+        const expected = (n * (n + 1)) / 2;
+
+        return expected - sum;
+    }
+}

reorder-list/HoonDongKang.ts

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+/**
+ * [Problem]: [143] Reorder List
+ * (https://leetcode.com/problems/reorder-list/)
+ */
+
+class ListNode {
+    val: number;
+    next: ListNode | null;
+    constructor(val?: number, next?: ListNode | null) {
+        this.val = val === undefined ? 0 : val;
+        this.next = next === undefined ? null : next;
+    }
+}
+
+/**
+ Do not return anything, modify head in-place instead.
+ */
+function reorderList(head: ListNode | null): void {
+    //시간복잡도 O(n)
+    //공간복잡도 O(n)
+    function stackFunc(head: ListNode | null): void {
+        if (!head || !head.next) return;
+
+        const stack: ListNode[] = [];
+        let node: ListNode | null = head;
+
+        while (node) {
+            stack.push(node);
+            node = node.next;
+        }
+
+        const length = stack.length;
+        node = head;
+
+        for (let i = 0; i < Math.floor(length / 2); i++) {
+            const tail = stack.pop()!;
+            const next: ListNode | null = node.next;
+
+            node.next = tail;
+            tail.next = next;
+
+            node = next!;
+        }
+
+        node.next = null;
+    }
+    //시간복잡도 O(n)
+    //공간복잡도 O(1)
+    function twoPointerFunc(head: ListNode | null): void {
+        if (!head || !head.next) return;
+
+        let slow = head;
+        let fast = head;
+        while (fast && fast.next && fast.next.next) {
+            slow = slow.next!;
+            fast = fast.next.next;
+        }
+
+        let prev: ListNode | null = null;
+        let curr = slow.next;
+        slow.next = null;
+
+        while (curr) {
+            const next = curr.next;
+            curr.next = prev;
+            prev = curr;
+            curr = next;
+        }
+
+        let first = head;
+        let second = prev;
+
+        while (second) {
+            const tmp1 = first!.next;
+            const tmp2 = second.next;
+
+            first!.next = second;
+            second.next = tmp1;
+
+            first = tmp1!;
+            second = tmp2;
+        }
+    }
+}