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problem0051.cpp
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#include <iostream>
#include <vector>
#include <utility>
#include <cstring>
#include <cmath>
#define MAX 1000000
int next_prime(int p, bool s[]);
void del_mult(int p, bool s[]);
int valid_prime(int p);
int digits(std::pair<int, int> n);
int family(std::pair<int, int> n, int change, bool s[]);
int main() {
bool sieve[MAX];
memset(sieve, true, sizeof(sieve));
sieve[0] = false;
sieve[1] = false;
int prime = 2;
// Fill in the sieve
for (int i = 0; i * i < MAX; ++i) {
del_mult(prime, sieve);
prime = next_prime(prime, sieve);
}
std::vector<int> primes;
// Create a vector of prime numbers
for (int i = 0; i < MAX; i++) {
if (sieve[i])
primes.push_back(i);
}
std::vector<std::pair<int, int>> rpt_primes;
int tmp;
for (int i : primes) {
tmp = valid_prime(i);
if (tmp >= 0)
rpt_primes.push_back(std::make_pair(i, tmp));
}
for (auto i : rpt_primes) {
if (family(i, digits(i), sieve) == 8) {
std::cout << i.first << std::endl;
}
}
return 0;
}
int next_prime(int p, bool s[]) {
while (!s[++p]);
return p;
}
void del_mult(int p, bool s[]) {
for (int i = p * p; i < MAX; i += p)
s[i] = false;
}
int valid_prime(int p) {
int occur[10] = {0};
p /= 10;
while (p > 0) {
++occur[p%10];
p /= 10;
}
if (occur[0] >= 3)
return 0;
if (occur[1] >= 3)
return 1;
if (occur[2] >= 3)
return 1;
return -1;
}
int digits(std::pair<int, int> n) {
int tmp = n.first;
int power = 1;
int dig = 0;
tmp /= 10;
while (tmp > 0) {
if (tmp % 10 == n.second) {
dig += static_cast<int>(pow(10, power));
}
++power;
tmp /= 10;
}
return dig;
}
int family(std::pair<int, int> n, int change, bool s[]) {
int size = 1;
int p = n.first;
int lim = 9 - n.second;
for (int i = 0; i < lim; ++i) {
p += change;
if (s[p])
++size;
}
return size;
}