feat: Add kosajura algorithm for finding strong connected components (TheAlgorithms#218)

Author: caojoshua

graph/kosajaru.ts

@@ -0,0 +1,75 @@
+// Compute the node priorities, which will be used to determine the order in which we perform transposed DFS.
+const getNodePriorities = (graph: number[][], visited: boolean[], stack: number[], node: number) => {
+  if (visited[node]) {
+    return;
+  }
+  visited[node] = true;
+
+  for (const dest of graph[node]) {
+    getNodePriorities(graph, visited, stack, dest);
+  }
+  // Nodes that end their DFS earlier are pushed onto the stack first and have lower priority.
+  stack.push(node);
+}
+
+// Return the transpose of graph. The tranpose of a directed graph is a graph where each of the edges are flipped.
+const transpose = (graph: number[][]): number[][] => {
+  let transposedGraph = Array(graph.length);
+  for (let i = 0; i < graph.length; ++i) {
+    transposedGraph[i] = [];
+  }
+
+  for (let i = 0; i < graph.length; ++i) {
+    for (let j = 0; j < graph[i].length; ++j) {
+      transposedGraph[graph[i][j]].push(i);
+    }
+  }
+
+  return transposedGraph;
+}
+
+// Computes the SCC that contains the given node
+const gatherScc = (graph: number[][], visited: boolean[], node: number, scc: number[]) => {
+  if (visited[node]) {
+    return;
+  }
+  visited[node] = true;
+  scc.push(node);
+
+  for (const dest of graph[node]) {
+    gatherScc(graph, visited, dest, scc);
+  }
+}
+
+/**
+ * @function kosajaru
+ * @description Given a graph, find the strongly connected components(SCC). A set of nodes form a SCC if there is a path between all pairs of points within that set.
+ * @Complexity_Analysis
+ * Time complexity: O(V + E). We perform two DFS twice, and make sure to visit each disconnected graph. Each DFS is O(V + E).
+ * Space Complexity: O(V + E). This space is required for the transposed graph.
+ * @param {[number, number][][]} graph - The graph in adjacency list form
+ * @return {number[][]} - An array of SCCs, where an SCC is an array with the indices of each node within that SCC.
+ * @see https://en.wikipedia.org/wiki/Kosaraju%27s_algorithm
+ */
+export const kosajaru = (graph: number[][]): number[][] => {
+  let visited = Array(graph.length).fill(false);
+
+  let stack: number[] = [];
+  for (let i = 0; i < graph.length; ++i) {
+    getNodePriorities(graph, visited, stack, i);
+  }
+
+  const transposedGraph = transpose(graph);
+
+  let sccs = [];
+  visited.fill(false);
+  for (let i = stack.length - 1; i >= 0; --i) {
+    if (!visited[stack[i]]) {
+      let scc: number[] = [];
+      gatherScc(transposedGraph, visited, stack[i], scc);
+      sccs.push(scc);
+    }
+  }
+  return sccs;
+}
+

graph/test/kosajaru.test.ts

@@ -0,0 +1,72 @@
+import { kosajaru } from "../kosajaru";
+
+describe("kosajaru", () => {
+
+  it("it should return no sccs for empty graph", () => {
+    expect(kosajaru([])).toStrictEqual([]);
+  });
+
+  it("it should return one scc for graph with one element", () => {
+    expect(kosajaru([[]])).toStrictEqual([[0]]);
+  });
+
+  it("it should return one scc for graph with element that points to itself", () => {
+    expect(kosajaru([[0]])).toStrictEqual([[0]]);
+  });
+
+  it("it should return one scc for two element graph with cycle", () => {
+    expect(kosajaru([[1], [0]])).toStrictEqual([[0, 1]]);
+  });
+
+  it("should return one scc for each element for straight line", () => {
+    expect(kosajaru([[1], [2], [3], []])).toStrictEqual([[0], [1], [2], [3]]);
+  });
+
+  it("should return sccs for straight line with backedge in middle", () => {
+    expect(kosajaru([[1], [2], [3, 0], []])).toStrictEqual([[0, 2, 1], [3]]);
+  });
+
+  it("should return sccs for straight line with backedge from end to middle", () => {
+    expect(kosajaru([[1], [2], [3], [1]])).toStrictEqual([[0], [1, 3, 2]]);
+  });
+
+  it("should return scc for each element for graph with no edges", () => {
+    expect(kosajaru([[], [], [], []])).toStrictEqual([[3], [2], [1], [0]]);
+  });
+
+  it("should return sccs disconnected graph", () => {
+    expect(kosajaru([[1, 2], [0, 2], [0, 1], []])).toStrictEqual([[3], [0, 1, 2]]);
+  });
+
+  it("should return sccs disconnected graph", () => {
+    expect(kosajaru([[1, 2], [0, 2], [0, 1], [4], [5], [3]])).toStrictEqual([[3, 5, 4], [0, 1, 2]]);
+  });
+
+  it("should return single scc", () => {
+    expect(kosajaru([[1], [2], [3], [0, 4], [3]])).toStrictEqual([[0, 3, 2, 1, 4]]);
+  });
+
+  it("should return one scc for complete connected graph", () => {
+    const input = [[1, 2, 3, 4], [0, 2, 3, 4], [0, 1, 3, 4], [0, 1, 2, 4], [0, 1, 2, 3]];
+    expect(kosajaru(input)).toStrictEqual([[0, 1, 2, 3, 4]]);
+  });
+
+  it("should return sccs", () => {
+    const input = [[1], [2], [0, 3], [4], []];
+    expect(kosajaru(input)).toStrictEqual([[0, 2, 1], [3], [4]]);
+  });
+
+  it("should return sccs", () => {
+    const input = [[1], [2], [0, 3, 4], [0], [5], [6, 7], [2, 4], [8], [5, 9], [5]];
+    const expected = [[0, 2, 1, 6, 5, 4, 8, 7, 9, 3]];
+    expect(kosajaru(input)).toStrictEqual(expected);
+  });
+
+  it("should return sccs", () => {
+    const input = [[1], [0, 2], [0, 3], [4], [5, 7], [6], [4, 7], []];
+    const expected = [[0, 1, 2], [3], [4, 6, 5], [7]];
+    expect(kosajaru(input)).toStrictEqual(expected);
+  });
+
+})
+