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| 1 | +What else? |
| 2 | + -BinarySearch in Integer Domain. |
| 3 | + -BinarySearch in Real Domain. |
| 4 | + |
| 5 | +Terminology: |
| 6 | + Search Space |
| 7 | + low |
| 8 | + high |
| 9 | + median |
| 10 | + Check function |
| 11 | + |
| 12 | +You can solve the problem using BinarySearch if and only if: |
| 13 | +- You can design a check function whose domain is the problem's search space |
| 14 | + and its range is separated into at most one "False" segment and one "True" segment. |
| 15 | +
|
| 16 | +
|
| 17 | +Can you design the upper_bound function? |
| 18 | +
|
| 19 | +bool isGreater(int a, int b){ |
| 20 | + return a > b; |
| 21 | +} |
| 22 | +
|
| 23 | +int upperBound(int *A, int val){ |
| 24 | + int lo = 0, med, hi = n-1; |
| 25 | + while(lo<hi){ |
| 26 | + mid = (lo+hi)>>1; |
| 27 | + if(isGreater(A[med], val)) hi = mid; |
| 28 | + else lo = med+1; |
| 29 | + } |
| 30 | + return lo; |
| 31 | +} |
| 32 | +
|
| 33 | +
|
| 34 | +We have two cases: |
| 35 | +1- Minimization Problems: |
| 36 | + -FFFFFFFFFFFFFFFFFFFTTTTTTTTTTTTTTTT |
| 37 | + -the range is separated into False-True range. |
| 38 | + -the target is the first True |
| 39 | + -We ceil the low and floor the median. |
| 40 | +
|
| 41 | +bool ok(int val){ |
| 42 | + //Some Checking Statements |
| 43 | +} |
| 44 | +
|
| 45 | +int binarySearch(){ |
| 46 | + int lo = 0, med, hi = 1000000000; |
| 47 | + while(lo<hi){ |
| 48 | + mid = (lo+hi)>>1; |
| 49 | + if(ok(A[med])) hi = med; |
| 50 | + else lo = med+1; |
| 51 | + } |
| 52 | + return hi; |
| 53 | +} |
| 54 | +
|
| 55 | +2- Maximization Problems: |
| 56 | + -TTTTTTTTTTTTTTTFFFFFFFFFFFFFFF |
| 57 | + -the range is separated into True-False range. |
| 58 | + -the target is the last True. |
| 59 | + -We ceil the median and floor the high. |
| 60 | +
|
| 61 | +bool ok(int val){ |
| 62 | + //Some Checking Statements |
| 63 | +} |
| 64 | +
|
| 65 | +int binarySearch(){ |
| 66 | + int lo = 0, med, hi = 1000000000; |
| 67 | + while(lo<hi){ |
| 68 | + mid = (lo+hi+1)>>1; |
| 69 | + if(ok(A[med])) lo = med; |
| 70 | + else hi = med-1; |
| 71 | + } |
| 72 | + return lo; |
| 73 | +} |
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