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Add challange for money bills calculation
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‎challenge-2-padlock-secret.ipynb

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"source": [
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"# Challenge 2 - Padlock Secret\n",
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"\n",
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"**Difficulty level**: 0 - beginner\n",
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"**Difficulty level**: 3 - beginner\n",
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"\n",
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"One approach to find a password or a padlock secret combination is to use a brute force attack. Of course, for a small combination it is not a big deal, but for complex combination it could be almost impossible using the current computation power.\n",
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"\n",
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"source": [
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"## Socket example\n",
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"\n",
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"This example shows how to create a socket and a client that communicate between them.\n",
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"This example shows how to create a socket and a client that communicates between them.\n",
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"It uses `multiprocessing.Process` to run the server and client code in a different system process.\n",
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"Using this approach, we can run server and client code in parallel."
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]

‎challenge-3-money-calculation.ipynb

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Money calculation\n",
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"\n",
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"**Difficulty level**: 1 - beginner\n",
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"\n",
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"Imagine you need to create a calculation that, for a given amount of money, it will return the number of each \n",
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"bill and coin you need to reach that amount. The priority order for the bills is from the highest bill to the smallest coin.\n",
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"\n",
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"Assumptions:\n",
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"\n",
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"- Available bills: `100$`, `50$`, `20$`, `10$` and `5$`\n",
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"- Available coins: `1$`, `0.5$`, `0.1$`, `0.05$` and `0.01$`\n",
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"- The largest bill/coin has priority compared to the smallest one.\n",
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"- The return of the function should be a dictionary, where the keys are represented by the nominal value of the \n",
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" bill/coin and the values are represented bty the number of bills/coins needed.\n",
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"- Float is not a precise data format, use `decimal.Decimal` instead.\n",
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" \n",
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"Tips:\n",
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"\n",
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"- Some functions that you will need for this challenge: \n",
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" - `for` loop.\n",
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" - the dictionary `keys` method.\n",
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" - string slicing.\n",
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" - casting from string to decimal using `decimal.Decimal` method.\n",
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" - for a division with no rest use `//`.\n",
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" - cast a decimal or float number to integer using `int` method.\n",
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"\n",
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"Example:\n",
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"\n",
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"```python\n",
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">>> amount = 87.16\n",
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">>> get_total_bills_and_coins(amount)\n",
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"{\n",
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" \"100$\": 0, \n",
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" \"50$\": 1,\n",
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" \"20$\": 1,\n",
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" \"10$\": 1,\n",
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" \"5$\": 1,\n",
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" \"1$\": 2,\n",
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" \"0.5$\": 0,\n",
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" \"0.1$\": 1,\n",
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" \"0.05$\": 1,\n",
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" \"0.01$\": 1\n",
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"}\n",
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"```"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"from decimal import Decimal\n",
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"\n",
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"\n",
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"def get_total_bills_and_coins(amount):\n",
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" n_bills = {\n",
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" \"100$\": 0, \n",
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" \"50$\": 0,\n",
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" \"20$\": 0,\n",
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" \"10$\": 0,\n",
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" \"5$\": 0,\n",
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" \"1$\": 0,\n",
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" \"0.5$\": 0,\n",
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" \"0.1$\": 0,\n",
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" \"0.05$\": 0,\n",
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" \"0.01$\": 0\n",
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" }\n",
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" \n",
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" for k in n_bills.keys():\n",
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" # YOUR CODE HERE\n",
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" \n",
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" return n_bills\n",
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" \n",
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" \n",
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"amount = Decimal('87.16')\n",
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"n_bills = get_total_bills_and_coins(amount)\n",
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"\n",
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"expected = {\n",
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" \"100$\": 0, \n",
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" \"50$\": 1,\n",
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" \"20$\": 1,\n",
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" \"10$\": 1,\n",
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" \"5$\": 1,\n",
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" \"1$\": 2,\n",
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" \"0.5$\": 0,\n",
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" \"0.1$\": 1,\n",
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" \"0.05$\": 1,\n",
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" \"0.01$\": 1\n",
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"}\n",
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"\n",
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"assert n_bills == expected"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## References\n",
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"\n",
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"- https://realpython.com/python-for-loop/\n",
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"- https://realpython.com/python-dicts/\n",
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"- https://realpython.com/python-strings/#string-slicing\n",
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"- https://realpython.com/python-rounding/#the-decimal-class\n",
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"- https://realpython.com/python-operators-expressions/#arithmetic-operators\n",
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"- https://www.peterbe.com/plog/interesting-casting-in-python"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.5"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

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