Hi,
I am trying to locate all low-rank UMTCs by rank and chiral central charge. However, at the rank 4, I encounter some problem. To my understanding of the PMFC convention, the category index labels all solutions of the pentagon equation and the braid index labels all solution of the hexagon equation when the solution of the pentagon equation is fixed. Therefore, in rank 4, for UniqueFusion category, if the self-duality number is zero, then the fusion ring solution is uniquely fixed to be $\mathbb{Z}_2 \times \mathbb{Z}_2$. Therefore we need to consider categories of the form PMFC{4(rank 4), 1(no multiplicity), 0(all objects are self-dual), 1(group-like fusion ring), x(some solutions of the pentagon equation), y(some solutions of the hexagon equation)}.
The trivial solution of the pentagon equation should at least include the following ones, when x = 0:
- $\mathrm{Rep}(\mathbb{Z}_2 \times \mathbb{Z}_2)$
- $\mathrm{Rep}(\mathbb{Z}_2) \boxtimes \mathrm{sVec}$
- $Z(\mathrm{Rep}(\mathbb{Z}_2))$
Indeed, I find there are three categories PMFC{4, 1, 0, 1, 0, 0}, PMFC{4, 1, 0, 1, 0, 1} and PMFC{4, 1, 0, 1, 0, 2} in CategoryData. These three exactly matches the above three categories.
When we choose the second solution to the pentagon equation, we should at least have the following ones, when x = 1:
- $Z(\mathrm{Semion})$
- $\mathrm{Semion} \boxtimes \mathrm{Semion}$
- $\mathrm{Semion} \boxtimes \mathrm{sVec}$
- $\overline{\mathrm{Semion}} \boxtimes \overline{\mathrm{Semion}}$
However, there are only three solutions PMFC{4, 1, 0, 1, 1, 0}, PMFC{4, 1, 0, 1, 1, 1} and PMFC{4, 1, 0, 1, 1, 2}, corresponding to the above first three categories. I cannot find the PMFC{4, 1, 0, 1, 1, 3}, which may correspond to the 4-th one.
Edit: For trivial associator with $\mathbb{Z}_2 \times \mathbb{Z}_2$ fusion rule, there exists another three-fermion UMTC, whose $c = 4 \mod 8$. Would it be PMFC{4, 1, 0, 1, 0, 3}? But there is no such label.
Edit: Now I don't think $\mathrm{Semion} \boxtimes \mathrm{sVec}$ shares the same F-symbol with $\mathrm{Semion} \boxtimes \mathrm{Semion}$ and $\overline{\mathrm{Semion}} \boxtimes \overline{\mathrm{Semion}}$. They are definitely different as $H^3(\mathbb{Z}_2 \times \mathbb{Z}_2, U(1))\simeq \mathbb{Z}_2^3$. But still very confused. The twist should be a gauge-independent data.
Hi,
I am trying to locate all low-rank UMTCs by rank and chiral central charge. However, at the rank 4, I encounter some problem. To my understanding of the$\mathbb{Z}_2 \times \mathbb{Z}_2$ . Therefore we need to consider categories of the form
PMFCconvention, the category index labels all solutions of the pentagon equation and the braid index labels all solution of the hexagon equation when the solution of the pentagon equation is fixed. Therefore, in rank 4, forUniqueFusioncategory, if the self-duality number is zero, then the fusion ring solution is uniquely fixed to bePMFC{4(rank 4), 1(no multiplicity), 0(all objects are self-dual), 1(group-like fusion ring), x(some solutions of the pentagon equation), y(some solutions of the hexagon equation)}.The trivial solution of the pentagon equation should at least include the following ones, when
x = 0:Indeed, I find there are three categories
PMFC{4, 1, 0, 1, 0, 0},PMFC{4, 1, 0, 1, 0, 1}andPMFC{4, 1, 0, 1, 0, 2}inCategoryData. These three exactly matches the above three categories.When we choose the second solution to the pentagon equation, we should at least have the following ones, when
x = 1:However, there are only three solutions
PMFC{4, 1, 0, 1, 1, 0},PMFC{4, 1, 0, 1, 1, 1}andPMFC{4, 1, 0, 1, 1, 2}, corresponding to the above first three categories. I cannot find thePMFC{4, 1, 0, 1, 1, 3}, which may correspond to the 4-th one.Edit: For trivial associator with$\mathbb{Z}_2 \times \mathbb{Z}_2$ fusion rule, there exists another three-fermion UMTC, whose $c = 4 \mod 8$ . Would it be
PMFC{4, 1, 0, 1, 0, 3}? But there is no such label.Edit: Now I don't think$\mathrm{Semion} \boxtimes \mathrm{sVec}$ shares the same F-symbol with $\mathrm{Semion} \boxtimes \mathrm{Semion}$ and $\overline{\mathrm{Semion}} \boxtimes \overline{\mathrm{Semion}}$ . They are definitely different as $H^3(\mathbb{Z}_2 \times \mathbb{Z}_2, U(1))\simeq \mathbb{Z}_2^3$ . But still very confused. The twist should be a gauge-independent data.