Fixed CUNYTechPrep#12 part 2 and cleaned up empty cells

Author: adonisja

homeworks/AT_intermediate-exercise_week3.ipynb

@@ -109,7 +109,7 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "## #3 Write a function that takes a list of numbers and returns True of all number in the list are unique and returns False if the list contains duplicate numbers. \n",
+    "## #3 Write a function that takes a list of numbers and returns True if all number in the list are unique and returns False if the list contains duplicate numbers. \n",
     "* Hint, maybe think of using a set()\n",
     "\n",
     "Input:  input_list = [2,4,5,5,7,9]\n",
@@ -167,7 +167,7 @@
   },
   {
    "cell_type": "code",
-   "execution_count": 5,
+   "execution_count": 53,
    "metadata": {},
    "outputs": [
     {
@@ -180,7 +180,6 @@
    ],
    "source": [
     "from collections import Counter\n",
-    "punctuations = [' ', '\\n', '-', ]\n",
     "\n",
     "with open('../Week-03/intermediate/data/lil-wayne.txt', 'r') as file:\n",
     "    text = file.read().upper()\n",
@@ -492,14 +491,14 @@
   },
   {
    "cell_type": "code",
-   "execution_count": 15,
+   "execution_count": 54,
    "metadata": {},
    "outputs": [
     {
      "name": "stdout",
      "output_type": "stream",
      "text": [
-      "11425.0\n"
+      "1142.5\n"
      ]
     }
    ],
@@ -508,31 +507,10 @@
     "word_per_page = 250\n",
     "number_of_pieces = 100\n",
     "\n",
-    "each_chunk = (457 * 250)/10\n",
+    "each_chunk = (457 * 250)/100\n",
     "print(each_chunk)"
    ]
   },
-  {
-   "cell_type": "code",
-   "execution_count": null,
-   "metadata": {},
-   "outputs": [],
-   "source": []
-  },
-  {
-   "cell_type": "code",
-   "execution_count": null,
-   "metadata": {},
-   "outputs": [],
-   "source": []
-  },
-  {
-   "cell_type": "code",
-   "execution_count": null,
-   "metadata": {},
-   "outputs": [],
-   "source": []
-  },
   {
    "cell_type": "markdown",
    "metadata": {},
@@ -1228,13 +1206,6 @@
     "# as (key/index, value) pairs...a dictionary if you will\n",
     "# After that its just a matter of manipulating the dictionary as needed "
    ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": null,
-   "metadata": {},
-   "outputs": [],
-   "source": []
   }
  ],
  "metadata": {