nbfghsd

Author: bekalue

0x03-debugging/3-convert_day.c

@@ -0,0 +1,53 @@
+#include "main.h"
+
+/**
+* convert_day - converts day of month to day of year, without accounting
+*		for leap year
+* @month: month in number format
+* @day: day of month
+*
+* Return: days of the year
+*/
+
+int convert_day(int month, int day)
+{
+	switch (month)
+	{
+	case 2:
+		day = 31 + day;
+		break;
+	case 3:
+		day = 59 + day;
+		break;
+	case 4:
+		day = 90 + day;
+		break;
+	case 5:
+		day = 120 + day;
+		break;
+	case 6:
+		day = 151 + day;
+		break;
+	case 7:
+		day = 181 + day;
+		break;
+	case 8:
+		day = 212 + day;
+		break;
+	case 9:
+		day = 243 + day;
+		break;
+	case 10:
+		day = 273 + day;
+		break;
+	case 11:
+		day = 304 + day;
+		break;
+	case 12:
+		day = 334 + day;
+		break;
+	default:
+		break;
+	}
+	return (day);
+}

0x03-debugging/3-print_remaining_days.c

@@ -0,0 +1,41 @@
+#include "main.h"
+
+/**
+* print_remaining_days - takes a date and prints how many days are
+*		left in the year, taking leap years into account
+*
+* @month: month in number format
+* @day: day of month
+* @year: year
+*/
+
+void print_remaining_days(int month, int day, int year)
+{
+	/**
+	 * leap year when it can be divided
+	 * by 100 and 400 or by 4 evenly
+	*/
+	if ((year % 100 == 0 && year % 400 == 0) || (year % 4 == 0))
+	{
+		if (month > 2 && day >= 60)
+		{
+			day++;
+		}
+
+		printf("Day of the year: %d\n", day);
+		printf("Remaining days: %d\n", 366 - day);
+
+	}
+	else
+	{
+		if (month == 2 && day == 60)
+		{
+			printf("Invalid date: %02d/%02d/%04d\n", month, day - 31, year);
+		}
+		else
+		{
+			printf("Day of the year: %d\n", day);
+			printf("Remaining days: %d\n", 365 - day);
+		}
+	}
+}