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MedianTwoSortedArrays_4.java
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120 lines (99 loc) · 4.29 KB
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/***
* The middle number. If there are two middle numbers, you average them
*/
public class Solution {
/***
* Every time cut half of the short array length from A & B
* Smaller than the smaller median can be cut
* Larger than the larger median can be cut
* untilt he short array has only 2 numbers.
* However the corner case is crazy, not suggest using this way
* so what we do is to binary search the position of those 2 numbers in the remaining longer array
* and return the median.
*/
/*
public double findMedianSortedArrays(int A[], int B[]) {
if (A.length == 0) return median(B, 0, B.length-1);
if (B.length == 0) return median(A, 0, A.length-1);
int s[], l[];
if (A.length <= B.length) { s = A; l = B; }
else { s = B; l = A; }
int lefts = 0, rights = s.length-1, leftl = 0, rightl = l.length-1;
int mids, midl, slide;
// until the shortest have two elements
while (lefts < rights - 1) {
mids = (lefts + rights)/2; midl = (leftl + rightl)/2;
slide = (rights - lefts)/2; // sliding is <= half of the short
if (s[mids] < l[midl]) {
lefts += slide; rightl -= slide;
} else if (s[mids] > l[midl]) {
rights -= slide; leftl += slide;
} else { // they are the same
lefts += slide; rightl -= slide;
rights -= slide; leftl += slide;
}
}
// corner cases drive me crazy, using binary insert instead.
// This is for correctness verficication
int length = rightl - leftl + 1 + rights - lefts + 1;
int remain[] = new int[length];
int i=leftl, j=lefts, index=0;
for(; i<=rightl && j<=rights; index++) {
if (l[i] < s[j]) { remain[index] = l[i]; i++; }
else { remain[index] = s[j]; j++; }
}
if (i > rightl) {
for (; j<=rights; j++, index++) {
remain[index] = s[j];
}
} else if (j > rights) {
for(; i<=rightl; i++, index++) {
remain[index] = l[i];
}
} else {
System.out.println("Somthing is Wrong!");
}
return median(remain, 0, length-1);
}*/
public double median(int arr[], int start, int end) {
int idx = (start + end) / 2;
if ((end - start) % 2 == 0 ) { return arr[idx]; // odd
} else { return (arr[idx] + arr[idx+1])/ 2.0 ; // even
}
}
public double findMedianSortedArrays(int A[], int B[]) {
// if (A.length == 0) return median(B, 0, B.length-1);
// if (B.length == 0) return median(A, 0, A.length-1);
int totallength = A.length + B.length;
int k = (A.length + B.length + 1) / 2; // the k-th smallest
if (totallength % 2 != 0) { // odd
return findkth(A, B, k);
}else {
return (findkth(A, B, k) + findkth(A, B, k+1))/2.0; // XXXXX 2.0 because of double
}
}
// arrays, k
public int findkth(int A[], int B[], int kth) {
int s[], l[];
if (A.length >= B.length) { l = A; s = B; }
else { l = B; s = A; }
int sleft = 0, lleft = 0; // the left index of l and s
int sk = 0, lk = 0; // the (k-1)/2 number of s & l
int k = kth;
while (true) {
if (s.length - sleft < 1) return l[k-1+lleft]; // the shorter one is empty
if (k == 1) return Math.min(s[sleft], l[lleft]);
int spart = Math.min(k/2, s.length-sleft);
int lpart = k - spart;
sk = s[spart+sleft-1]; lk = l[lpart+lleft-1];
if (sk == lk) return sk;
if (sk < lk) { sleft += spart; k -= spart; }
else { lleft += lpart; k -= lpart; }
if (s.length-sleft > l.length-lleft) { // XXX need to be the length - begin index
// exchange
int temparray[] = s; s = l; l = temparray;
int templeft = sleft; sleft = lleft; lleft = templeft;
}
}
}
}