Treat blank lines with a bunch of whitespace as a ;.

Author: mattdeboard

elixir-smie.el

@@ -112,15 +112,21 @@
     ;; The point here is that we want to treat blank lines as a single semi-
     ;; colon when it comes to detecting the end of match statements. This could
     ;; also be handled by a `while' expression or some other looping mechanism.
-    (if (and (eolp) (bolp))
-        (progn (forward-char)
-               (if (< (point) (point-max))
-                   (elixir-smie--semi-ends-match)
-                 nil))
-      ;; And if we're NOT on a blank line, move to the end of the line, and see
-      ;; if we're looking back at a block operator.
-      (progn (move-end-of-line 1)
-             (looking-back elixir-smie--block-operator-regexp)))))
+    (cond
+     ((and (eolp) (bolp))
+      (forward-char)
+      (if (< (point) (point-max))
+          (elixir-smie--semi-ends-match)
+        nil))
+     ((looking-at elixir-smie--spaces-til-eol-regexp)
+      (move-beginning-of-line 2)
+      (if (< (point) (point-max))
+          (elixir-smie--semi-ends-match)
+        nil))
+     ;; And if we're NOT on a blank line, move to the end of the line, and see
+     ;; if we're looking back at a block operator.
+     (t (move-end-of-line 1)
+        (looking-back elixir-smie--block-operator-regexp)))))
 
 (defun elixir-smie--same-line-as-parent (parent-pos child-pos)
   "Return non-nil if `child-pos' is on same line as `parent-pos'."