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112. Path Sum
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25 lines (25 loc) · 772 Bytes
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode* root, int targetSum) {
if(!root){
return false;
}
if(!root->left && !root->right){
return targetSum == root->val;
}
bool leftPath = hasPathSum(root->left , targetSum-root->val);
bool rightPath = hasPathSum(root->right,targetSum-root->val);
return leftPath || rightPath;
}
};