Does the update function not support CronWithSeconds? #188
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JohnRoesler
Chen840302
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This is my code, job ,_ := s.Every(3).Seconds().Do(job1.task, "123")
s.StartAsync()
time.Sleep(time.Second * 6)
s.Job(job).CronWithSeconds("*/3 * * * * *").Update() But it will show the following error message |
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Answered by
JohnRoesler
Jun 8, 2021
Replies: 1 comment 1 reply
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It’s likely that I missed adding update support for the cron functionality. I’ll check that out when I have time again (hopefully soon) |
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It’s likely that I missed adding update support for the cron functionality. I’ll check that out when I have time again (hopefully soon)