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Copy pathCyclically Rotating a Grid.java
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Cyclically Rotating a Grid.java
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class Solution {
public int[][] rotateGrid(int[][] grid, int k) {
int m = grid.length, n = grid[0].length, noOfLayers = Math.min(m/2, n/2);
// Peeling each layer one by one
for(int layerNo = 0; layerNo < noOfLayers; layerNo++){
// Please suggest if you have better way to find perimeter of matrix on a given layer!
int perimeter = (m-(2*layerNo)) + (n-(2*layerNo)-1) + (m-(2*layerNo)-1) + (n-(2*layerNo)-2);
int[] layer = new int[perimeter]; // this out be use to store that particular layer
readLayer(grid, layer, layerNo, m, n); // this will read the layer
writeLayer(grid, layer, layerNo, m, n, k); // this will rotate it by k and write back the layer
}
return grid;
}
public void readLayer(int[][] grid, int[] layer, int layerNo, int m, int n){
int count = 0, r = layerNo, c = layerNo;
m--; n--;
// read left a -> c
for(int i = layerNo; i < n - layerNo; i++) layer[count++] = grid[layerNo][i];
// read down c -> i
for(int i = layerNo; i < m - layerNo; i++) layer[count++] = grid[i][n-layerNo];
// read right i -> g
for(int i = n-layerNo; i > layerNo; i--) layer[count++] = grid[m-layerNo][i];
// read up g -> a
for(int i = m-layerNo; i > layerNo; i--) layer[count++] = grid[i][layerNo];
}
public void writeLayer(int[][] grid, int[] layer, int layerNo, int m, int n, int k){
m--; n--;
int len = layer.length, count = k;
// write left a -> c
for(int i = layerNo; i < n - layerNo; i++){
count %= len; // reason if goes out of length start back from 0
grid[layerNo][i] = layer[count++];
}
// write down c -> i
for(int i = layerNo; i < m - layerNo; i++){
count %= len;
grid[i][n-layerNo] = layer[count++];
}
// write right i -> g
for(int i = n-layerNo; i > layerNo; i--){
count %= len;
grid[m-layerNo][i] = layer[count++];
}
// write up g -> a
for(int i = m-layerNo; i > layerNo; i--){
count %= len;
grid[i][layerNo] = layer[count++];
}
}
}