Max Value of Equation.java

// Runtime: 16 ms (Top 80.93%) | Memory: 104.9 MB (Top 83.74%)
class Solution {
    public int findMaxValueOfEquation(int[][] points, int k) {
        int ans=Integer.MIN_VALUE;
        int i=0;
        int f=1;
        while(i < points.length) {
            if(f<i+1)
                f=i+1;
            for (int j = f; j <= points.length-1; j++) {
                if(points[j][0]>(points[i][0]+k))
                    break;
                if((points[i][1]+points[j][1]+points[j][0]-points[i][0])>ans){
                    ans=points[i][1]+points[j][1]+points[j][0]-points[i][0];
                    f=j-1;
                }
            }
            i++;
        }
        return ans;
    }
}