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‎1.Introduction to Python/Arithmetic Progression.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Arithmetic Progression\n",
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"You are given first three entries of an arithmetic progression. You have to calculate the common difference and print it.<br>\n",
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"<br>\n",
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"Input format:<br>\n",
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"The first line of input contains an integer a (1 <= a <= 100)<br>\n",
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"The second line of input contains an integer b (1 <= b <= 100) <br>\n",
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"The third line of input contains an integer c (1 <= c <= 100) <br>\n",
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"<br>\n",
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"Constraints:<br>\n",
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"Time Limit: 1 second<br>\n",
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"<br>\n",
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"Output format:<br>\n",
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"The first and only line of output contains the result. <br>\n",
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"<br>\n",
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"Sample Input:<br>\n",
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"1<br>\n",
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"3<br>\n",
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"5<br>\n",
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"Sample Output:<br>\n",
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"2"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"a=int(input())\n",
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"b=int(input())\n",
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"c=int(input())\n",
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"print(b-a)"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

‎1.Introduction to Python/Find X raised to power N.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Find X raised to power N\n",
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"You are given two integers: X and N. You have to calculate X raised to power N and print it.<br>\n",
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"<br>\n",
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"Input format:<br>\n",
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"The first line of input contains an integer X (1 <= X <= 100)<br>\n",
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"The second line of input contains an integer N (1 <= N <= 10) <br>\n",
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"<br>\n",
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"Constraints:<br>\n",
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"Time Limit: 1 second<br>\n",
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"<br>\n",
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"Output format:<br>\n",
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"The first and only line of output contains the result. <br>\n",
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"<br>\n",
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"Sample Input:<br>\n",
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"10<br>\n",
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"4<br>\n",
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"Sample Output:<br>\n",
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"10000"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"X=int(input())\n",
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"N=int(input())\n",
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"\n",
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"print(X**N)"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

‎1.Introduction to Python/Find average Marks.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Find average Marks\n",
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"Write a program to input marks of three tests of a student (all integers). Then calculate and print the average of all test marks.<br>\n",
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"<br>\n",
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"Input format :<br>\n",
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"3 Test marks (in different lines)<br>\n",
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"Output format :<br>\n",
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"Average<br>\n",
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"<br>\n",
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"Sample Input 1 :<br>\n",
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"3 <br>\n",
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"4 <br>\n",
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"6<br>\n",
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"Sample Output 1 :<br>\n",
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"4.333333333333333<br>\n",
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"<br>\n",
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"Sample Input 2 :<br>\n",
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"5 <br>\n",
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"10 <br>\n",
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"5<br>\n",
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"Sample Output 2 :<br>\n",
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"6.666666666666667"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"sub_1=int(input(\"\"))\n",
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"sub_2=int(input(\"\"))\n",
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"sub_3=int(input(\"\"))\n",
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"Average_of_3_subjects=(sub_1+sub_2+sub_3)\n",
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"print(Average_of_3_subjects/3)"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

‎1.Introduction to Python/Rectangular Area.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Rectangular Area\n",
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"You are given a rectangle in a plane. The corner coordinates of this rectangle is provided to you. You have to print the amount of area of the plane covered by this rectangles.<br>\n",
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"<br>\n",
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"The end coordinates are provided as four integral values: x1, y1, x2, y2. It is given that x1 < x2 and y1 < y2.<br>\n",
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"<br>\n",
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"Input format:<br>\n",
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"The first line of input contains an integer x1 (1 <= x1 <= 10)<br>\n",
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"The second line of input contains an integer y1 (1 <= y1 <= 10) <br>\n",
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"The third line of input contains an integer x2 (1 <= x2 <= 10)<br>\n",
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"The fourth line of input contains an integer y2 (1 <= y2 <= 10) <br>\n",
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"<br>\n",
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"Constraints:<br>\n",
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"Time Limit: 1 second<br>\n",
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"<br>\n",
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"Output format:<br>\n",
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"The first and only line of output contains the result.<br>\n",
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"<br>\n",
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"Sample Input:<br>\n",
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"1<br>\n",
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"1<br>\n",
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"3<br>\n",
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"3<br>\n",
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"Sample Output:<br>\n",
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"4"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"x1=int(input())\n",
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"y1=int(input())\n",
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"x2=int(input())\n",
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"y2=int(input())\n",
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"print((x2-x1)*(y2 - y1))"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

‎2.Conditionals and Loops/Calculator.ipynb‎

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Calculator<br>\n",
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"<br>\n",
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"Write a program that performs the tasks of a simple calculator. The program should first take an integer as input and then based on that integer perform the task as given below.<br>\n",
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"<br>\n",
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"1. If the input is 1, 2 integers are taken from the user and their sum is printed.<br>\n",
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"2. If the input is 2, 2 integers are taken from the user and their difference(1st number - 2nd number) is printed.<br>\n",
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"3. If the input is 3, 2 integers are taken from the user and their product is printed.<br>\n",
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"4. If the input is 4, 2 integers are taken from the user and the quotient obtained (on dividing 1st number by 2nd number) is printed.<br>\n",
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"5. If the input is 5, 2 integers are taken from the user and their remainder(1st number mod 2nd number) is printed.<br>\n",
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"6. If the input is 6, the program exits.<br>\n",
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"7. For any other input, print &quot;Invalid Operation&quot;.<br>\n",
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"Note: Each answer in next line.<br>\n",
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"<br>\n",
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"Input format:<br>\n",
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"Take integers as input, in accordance to the description of the question. <br>\n",
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"<br>\n",
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"Constraints:<br>\n",
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"Time Limit: 1 second<br>\n",
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"<br>\n",
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"Output format:<br>\n",
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"The output lines must be as prescribed in the description of the question.<br>\n",
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"<br>\n",
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"Sample Input:<br>\n",
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"3<br>\n",
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"1<br>\n",
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"2<br>\n",
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"4<br>\n",
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"4<br>\n",
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"2<br>\n",
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"1<br>\n",
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"3<br>\n",
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"2<br>\n",
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"7<br>\n",
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"6<br>\n",
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"Sample Output:<br>\n",
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"2<br>\n",
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"2<br>\n",
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"5<br>\n",
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"Invalid Operation"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": [
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"while True:\n",
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" n = int(input())\n",
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" if n == 1:\n",
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" n1 = int(input())\n",
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" n2 = int(input())\n",
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" print(int(n1+n2))\n",
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" elif n == 2:\n",
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" n1 = int(input())\n",
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" n2 = int(input())\n",
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" print(int(n1-n2))\n",
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" elif n == 3:\n",
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" n1 = int(input())\n",
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" n2 = int(input())\n",
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" print(int(n1*n2))\n",
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" elif n == 4:\n",
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" n1 = int(input())\n",
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" n2 = int(input())\n",
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" print(int(n1/n2))\n",
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" elif n == 5:\n",
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" n1 = int(input())\n",
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" n2 = int(input())\n",
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" print(int(n1//n2))\n",
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" elif n == 6:\n",
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" exit()\n",
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" else:\n",
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" print(\"Invalid Operation\")"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.6"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 4
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}

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