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| 1 | +class TreeNode { |
| 2 | + val: number; |
| 3 | + left: TreeNode | null; |
| 4 | + right: TreeNode | null; |
| 5 | + constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) { |
| 6 | + this.val = val === undefined ? 0 : val; |
| 7 | + this.left = left === undefined ? null : left; |
| 8 | + this.right = right === undefined ? null : right; |
| 9 | + } |
| 10 | +} |
| 11 | + |
| 12 | +/** |
| 13 | + * https://leetcode.com/problems/binary-tree-maximum-path-sum |
| 14 | + * T.C. O(n) |
| 15 | + * S.C. O(n) |
| 16 | + */ |
| 17 | +function maxPathSum(root: TreeNode | null): number { |
| 18 | + let max = -Infinity; |
| 19 | + |
| 20 | + function dfs(node: TreeNode | null): number { |
| 21 | + if (!node) return 0; |
| 22 | + |
| 23 | + const left = Math.max(0, dfs(node.left)); |
| 24 | + const right = Math.max(0, dfs(node.right)); |
| 25 | + |
| 26 | + max = Math.max(max, node.val + left + right); |
| 27 | + |
| 28 | + return node.val + Math.max(left, right); |
| 29 | + } |
| 30 | + |
| 31 | + dfs(root); |
| 32 | + |
| 33 | + return max; |
| 34 | +} |
| 35 | + |
| 36 | +/** |
| 37 | + * iterative using stack |
| 38 | + * T.C. O(n) |
| 39 | + * S.C. O(n) |
| 40 | + */ |
| 41 | +function maxPathSum(root: TreeNode | null): number { |
| 42 | + let max = -Infinity; |
| 43 | + const stack: Array<TreeNode | null> = [root]; |
| 44 | + const memo = new Map<TreeNode, number>(); |
| 45 | + |
| 46 | + while (stack.length) { |
| 47 | + const node = stack.pop(); |
| 48 | + |
| 49 | + if (!node) continue; |
| 50 | + |
| 51 | + if (memo.has(node)) { |
| 52 | + const left = Math.max(0, node.left ? memo.get(node.left)! : 0); |
| 53 | + const right = Math.max(0, node.right ? memo.get(node.right)! : 0); |
| 54 | + |
| 55 | + max = Math.max(max, node.val + left + right); |
| 56 | + |
| 57 | + memo.set(node, node.val + Math.max(left, right)); |
| 58 | + } else { |
| 59 | + stack.push(node, node.right, node.left); |
| 60 | + memo.set(node, 0); |
| 61 | + } |
| 62 | + } |
| 63 | + |
| 64 | + return max; |
| 65 | +} |
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