-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path206.reverse-linked-list.cpp
More file actions
68 lines (65 loc) · 1.41 KB
/
206.reverse-linked-list.cpp
File metadata and controls
68 lines (65 loc) · 1.41 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
/*
* @lc app=leetcode id=206 lang=cpp
*
* [206] Reverse Linked List
*
* https://leetcode.com/problems/reverse-linked-list/description/
*
* algorithms
* Easy (61.33%)
* Likes: 4542
* Dislikes: 90
* Total Accepted: 1M
* Total Submissions: 1.6M
* Testcase Example: '[1,2,3,4,5]'
*
* Reverse a singly linked list.
*
* Example:
*
*
* Input: 1->2->3->4->5->NULL
* Output: 5->4->3->2->1->NULL
*
*
* Follow up:
*
* A linked list can be reversed either iteratively or recursively. Could you
* implement both?
*
*/
// Definition for singly-linked list.
struct ListNode {
int val;
ListNode* next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode* next) : val(x), next(next) {}
};
// @lc code=start
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* reverseList(ListNode* head) {
ListNode* prev = nullptr;
ListNode* node = head;
ListNode* next = nullptr;
while (node != nullptr) {
next = node->next;
node->next = prev;
prev = node;
node = next;
}
return prev;
}
};
// @lc code=end