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The last test should return false because the values are as distinct as two different numbers.
The only issue is: how? I don’t think this would be possible without a global list of symbols that have been seen, but you really want a hash function to not depend on mutable global state, so … hm. You might be right, but this might just not be possible to do.
Symbols are unique, so the implementation added in #23 doesn't work as expected e.g.:
The last test should return false because the values are as distinct as two different numbers.
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