Scope of Python function called from C++

[danimasa]

Hello

Is there a way to call a function passing the scope like I can do with py::exec?

I'm doing it that way but I can't access the variable in the same scope of the function:

myfile.py

local_var = "test"

def my_func():
  print(local_var)

myfile.cpp

auto local = py::dict();
auto globals = py::globals();
py::eval_file("myfile.py", globals, local);
py::object func = local["my_func"];
func();

And it results in the following message: Name Error: name 'local_var' is not defined

[danimasa]

I find a way to read the local variables from inside the function. What I did was update the globals before running the function:

auto local = py::dict();
auto globals = py::globals();
py::eval_file("myfile.py", globals, local);
globals.attr("update")(locals);
py::object func = local["my_func"];
func();