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"..." is not recognised in function pointer declarations. #49

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@c99zealot

void (*f)(int, ...); is a valid declaration and should convert to English as something like declare f as pointer to function (int, ...) returning void but the output from cdecl is a syntax error, as shown in the image below.

image
https://cdecl.org/?q=void+%28*f%29%28int%2C+...%29%3B

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