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Search in a Rotated Array
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67 lines (57 loc) · 1.4 KB
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/*
Given a sorted and rotated array A of N distinct elements which is rotated at some point,
and given an element K. The task is to find the index of the given element K in the array A.
*/
#include <iostream>
using namespace std;
int binary_search(long long int arr[], int l, int r, long long int k)
{
if(l > r) {
return -1;
}
int mid = (l + r) / 2;
if(arr[mid] == k) {
return mid;
} else if(k > arr[mid]) {
return binary_search(arr, mid+1, r, k);
} else {
return binary_search(arr, l, mid-1, k);
}
}
int search(long long int arr[], int l, int r)
{
if(arr[l] < arr[r]) {
return l;
}
int mid = (l + r) / 2;
if(arr[mid] > arr[mid+1]) {
return mid+1;
}
if(arr[l] < arr[mid]) {
return search(arr, mid + 1, r);
} else {
return search(arr, l, mid-1);
}
}
int main() {
int n;
cin >> n;
long long int arr[n];
for(int i = 0; i < n; i++) {
cin >> arr[i];
}
long long int k;
cin >> k;
int pivot = search(arr, 0, n-1);
// cout << pivot << endl;
if(pivot == 0) {
cout << binary_search(arr, 0, n-1, k) << endl;
} else {
if(k >= arr[0] && k <= arr[pivot-1]) {
cout << binary_search(arr, 0, pivot-1, k) << endl;
} else {
cout << binary_search(arr, pivot, n-1, k) << endl;
}
}
return 0;
}