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The temperature is not constant at an isothermal wall BC #1895
Answered by
WallyMaier
Jan 20, 2023
Replies: 2 comments 1 reply
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Hi |
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Hi, The Isothermal wall condition behavior seems to be OK. The isothermal wall is a weakly enforced boundary condition, so we don't set the fluid temperature at the wall to be a certain temperature. The saw-tooth pattern is odd, and may be due to the numerical inaccuracies caused by the symmetry plane. |
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Answer selected by
LDK29
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Hi,
Regarding the symmetry boundary, this is a known issue in the SU2 solver, and we often avoid this by simulating a full domain....I know it isn't as computationally efficient.
The Isothermal wall condition behavior seems to be OK. The isothermal wall is a weakly enforced boundary condition, so we don't set the fluid temperature at the wall to be a certain temperature. The saw-tooth pattern is odd, and may be due to the numerical inaccuracies caused by the symmetry plane.