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Added Consecutive User Logins
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‎Consecutive User Logins/READme.md

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# Consecutive User Logins
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![Star Badge](https://img.shields.io/static/v1?label=%F0%9F%8C%9F&message=If%20Useful&style=style=flat&color=BC4E99)
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[![View Main Folder](https://img.shields.io/badge/View-Main_Folder-971901?)](https://github.com/thecoddiwompler/SQL-Practice-Questions/tree/main)
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[![View Repositories](https://img.shields.io/badge/View-My_Repositories-blue?logo=GitHub)](https://github.com/thecoddiwompler?tab=repositories)
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[![View My Profile](https://img.shields.io/badge/View-My_Profile-green?logo=GitHub)](https://github.com/thecoddiwompler)
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---
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## 🛠️ Problem Statement
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<b>Table Name : user_login</b>
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| Column Name |Type |
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| ------------- | ------------- |
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| user_id | int |
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| login_date | date |
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This table shows the date when each user logged in to the system. <br/><br>
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Write a SQL query to identify the users who logged in for 5 or more consecutive days. Return the user id, start date, end date, and no of consecutive days.
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<br><br>
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Please remember a user can login multiple times during a day but only consider users whose consecutive logins spanned 5 days or more.
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<br/>
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The query result format is in the following example:
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<details>
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<summary>
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Input
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</summary>
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<br>
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<b> Table Name: user_login <br><br>
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| user_id | login_date |
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|---------|-------------|
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| 1 | 01/03/2024 |
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| 1 | 02/03/2024 |
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| 1 | 03/03/2024 |
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| 1 | 04/03/2024 |
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| 1 | 06/03/2024 |
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| 1 | 10/03/2024 |
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| 1 | 11/03/2024 |
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| 1 | 12/03/2024 |
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| 1 | 13/03/2024 |
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| 1 | 14/03/2024 |
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| 1 | 20/03/2024 |
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| 1 | 25/03/2024 |
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| 1 | 26/03/2024 |
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| 1 | 27/03/2024 |
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| 1 | 28/03/2024 |
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| 1 | 29/03/2024 |
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| 1 | 30/03/2024 |
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| 2 | 01/03/2024 |
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| 2 | 02/03/2024 |
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| 2 | 03/03/2024 |
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| 2 | 04/03/2024 |
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| 3 | 01/03/2024 |
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| 3 | 02/03/2024 |
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| 3 | 03/03/2024 |
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| 3 | 04/03/2024 |
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| 3 | 04/03/2024 |
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| 3 | 04/03/2024 |
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| 3 | 05/03/2024 |
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| 4 | 01/03/2024 |
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| 4 | 02/03/2024 |
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| 4 | 03/03/2024 |
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| 4 | 04/03/2024 |
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| 4 | 04/03/2024 |
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</details>
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<details>
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<summary>
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Output <br><br>
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</summary>
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| user_id | start_date | end_date | consecutive_days |
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|---------|------------|------------|------------------|
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| 1 | 2024-03-10 | 2024-03-14 | 5 |
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| 1 | 2024-03-25 | 2024-03-30 | 6 |
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| 3 | 2024-03-01 | 2024-03-05 | 5 |
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</details>
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---

‎Consecutive User Logins/schema.sql

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drop table if exists user_login;
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create table user_login
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(
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user_id int,
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login_date date
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);
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INSERT INTO user_login (user_id, login_date)
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VALUES
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(1, to_date('01/03/2024','dd/mm/yyyy')),
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(1, to_date('02/03/2024','dd/mm/yyyy')),
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(1, to_date('03/03/2024','dd/mm/yyyy')),
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(1, to_date('04/03/2024','dd/mm/yyyy')),
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(1, to_date('06/03/2024','dd/mm/yyyy')),
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(1, to_date('10/03/2024','dd/mm/yyyy')),
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(1, to_date('11/03/2024','dd/mm/yyyy')),
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(1, to_date('12/03/2024','dd/mm/yyyy')),
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(1, to_date('13/03/2024','dd/mm/yyyy')),
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(1, to_date('14/03/2024','dd/mm/yyyy')),
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(1, to_date('20/03/2024','dd/mm/yyyy')),
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(1, to_date('25/03/2024','dd/mm/yyyy')),
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(1, to_date('26/03/2024','dd/mm/yyyy')),
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(1, to_date('27/03/2024','dd/mm/yyyy')),
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(1, to_date('28/03/2024','dd/mm/yyyy')),
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(1, to_date('29/03/2024','dd/mm/yyyy')),
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(1, to_date('30/03/2024','dd/mm/yyyy')),
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(2, to_date('01/03/2024','dd/mm/yyyy')),
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(2, to_date('02/03/2024','dd/mm/yyyy')),
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(2, to_date('03/03/2024','dd/mm/yyyy')),
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(2, to_date('04/03/2024','dd/mm/yyyy')),
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(3, to_date('01/03/2024','dd/mm/yyyy')),
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(3, to_date('02/03/2024','dd/mm/yyyy')),
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(3, to_date('03/03/2024','dd/mm/yyyy')),
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(3, to_date('04/03/2024','dd/mm/yyyy')),
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(3, to_date('04/03/2024','dd/mm/yyyy')),
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(3, to_date('04/03/2024','dd/mm/yyyy')),
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(3, to_date('05/03/2024','dd/mm/yyyy')),
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(4, to_date('01/03/2024','dd/mm/yyyy')),
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(4, to_date('02/03/2024','dd/mm/yyyy')),
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(4, to_date('03/03/2024','dd/mm/yyyy')),
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(4, to_date('04/03/2024','dd/mm/yyyy')),
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(4, to_date('04/03/2024','dd/mm/yyyy'));

‎Consecutive User Logins/solution.sql

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WITH distinct_user_login AS (
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SELECT
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DISTINCT user_id,
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login_date
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FROM
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user_login
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),
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ranked_user_login AS (
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SELECT
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user_id,
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login_date,
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rank() over(
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PARTITION by user_id
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ORDER BY
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login_date
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) rnk
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FROM
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distinct_user_login
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),
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all_consecutive_login AS (
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SELECT
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a.user_id,
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b.login_date start_date,
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a.login_date end_date
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FROM
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ranked_user_login a
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INNER JOIN ranked_user_login b ON a.login_date > b.login_date
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AND a.user_id = b.user_id
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AND a.login_date - b.login_date = a.rnk - b.rnk
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),
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filtered_start_date AS (
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SELECT
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user_id,
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start_date,
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max(end_date) end_date
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FROM
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all_consecutive_login
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GROUP BY
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user_id,
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start_date
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),
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filtered_end_date AS (
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SELECT
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user_id,
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min(start_date) start_date,
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end_date
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FROM
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filtered_start_date
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GROUP BY
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user_id,
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end_date
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)
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SELECT
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user_id,
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start_date,
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end_date,
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end_date - start_date + 1 consecutive_days
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FROM
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filtered_end_date
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WHERE
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end_date - start_date + 1 >= 5
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ORDER BY
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user_id;

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