Merge pull request #356 from saurabh22111999/j

added solution (Alternative Square Pattern)

Author: 8-bit-souvik

CodeChef DSA Learning series Solutions/Easy Problems to get started/Alternative Square Pattern/README.md

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+Alternative Square Pattern Problem Code: SQALPAT
+Add problem to Todo list
+
+You're given a number N. Print the first N lines of the below-given pattern.
+
+1 2 3 4 5
+10 9 8 7 6
+11 12 13 14 15
+20 19 18 17 16
+21 22 23 24 25
+30 29 28 27 26
+Input:
+First-line will contain the number N.
+Output:
+Print the first N lines of the given pattern.
+
+Constraints
+1≤N≤200
+Sample Input 1:
+4
+Sample Output 1:
+1 2 3 4 5
+10 9 8 7 6
+11 12 13 14 15
+20 19 18 17 16
+Sample Input 2:
+2
+Sample Output 2:
+1 2 3 4 5
+10 9 8 7 6
+EXPLANATION:
+In the first example, we'll print the first 4 lines of the given pattern.
+In the second example, we'll print the first 2 lines of the given pattern.

CodeChef DSA Learning series Solutions/Easy Problems to get started/Alternative Square Pattern/Solution.cpp

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+#include <iostream>
+using namespace std;
+
+int main() {
+    int n;
+    cin>>n;
+    int sumi = 0, sumj = 10;
+    for(int i=1; i<=n; i++){
+        if(i%2!=0){
+            for(int j=sumi+1; j<=sumi+5; j++){
+                cout<<j<<" ";
+            }
+            cout<<endl;
+            sumi = sumi + 10;
+        }else{
+            for(int j=sumj; j>=sumj-4; j--){
+                cout<<j<<" ";
+            }
+            cout<<endl;
+            sumj = sumj + 10;
+        }
+    }
+    return 0;
+}

CodeChef DSA Learning series Solutions/Easy Problems to get started/Sum Is Everywhere/README.md

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+Sum Is Everywhere Problem Code: SUMEVOD
+Add problem to Todo list
+
+You are given a number N and find the sum of the first N odd and even numbers in a line separated by space. All even and odd numbers should be greater than 0.
+
+Input:
+First-line will contain the number N.
+Output:
+Print the sum of the first N odd and even numbers in a line separated by space.
+
+Constraints
+1≤N≤106
+Sample Input 1:
+4
+Sample Output 1:
+16 20
+Sample Input 2:
+1
+Sample Output 2:
+1 2
+EXPLANATION:
+In the first example, (1 + 3 + 5 + 7) = 16 and (2 + 4 + 6 + 8) = 20.
+In the second example, only one odd that is 1 and only one even that is 2.

CodeChef DSA Learning series Solutions/Easy Problems to get started/Sum Is Everywhere/Solution.cpp

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+#include <iostream>
+#define ll long long
+using namespace std;
+
+int main() {
+    // your code goes here
+    ll n,even,odd;
+
+    cin>>n;
+    even = n(n+1);
+    odd = nn;
+    cout<<odd<<" "<<even;
+
+    return 0;
+}

CodeChef DSA Learning series Solutions/Easy Problems to get started/Triangle Everywhere/README.md

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+Triangle Everywhere Problem Code: EXTRICHK
+Add problem to Todo list
+
+You're given the length of three sides a, b, and c respectively. Now If these three sides can form an Equilateral Triangle then print 1, if these three sides can form an Isosceles Triangle then print 2, if these three sides can form a Scalene Triangle then print 3, otherwise print −1.
+
+Input:
+First-line will contain three numbers a, b, and c separated by space.
+Output:
+Print the answer in a new line.
+
+Constraints
+1≤a,b,c≤103
+Sample Input 1:
+2 4 3
+Sample Output 1:
+3
+Sample Input 2:
+4 4 4
+Sample Output 2:
+1
+Sample Input 3:
+4 4 9
+Sample Output 3:
+-1
+EXPLANATION:
+In the first example, (2, 4, 3) will form a Scalene Triangle.
+In the second example, (4, 4, 4) will form an Equilateral Triangle.
+In the third example, (4, 4, 9) will not form a triangle.

CodeChef DSA Learning series Solutions/Easy Problems to get started/Triangle Everywhere/Solution.cpp

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+#include <iostream>
+using namespace std;
+
+int main()
+{
+    int a, b, c;
+    cin >> a >> b >> c;
+    if (a + b > c && b + c > a && c + a > b)
+    {
+        if (a == b && b == c)
+            cout << "1";
+        else if (a == b  b == c  c == a)
+            cout << "2";
+        else
+            cout << "3";
+    }
+    else
+        cout << "-1";
+    return 0;
+}

CodeChef DSA Learning series Solutions/Easy Problems to get started/Triangle With Angle/README.md

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+Triangle With Angle Problem Code: ANGTRICH
+Add problem to Todo list
+
+You're given the three angles a, b, and c respectively. Now check if these three angles can form a valid triangle with an area greater than 0 or not. Print "YES"(without quotes) if it can form a valid triangle with an area greater than 0, otherwise print "NO" (without quotes).
+
+Input:
+First-line will contain three numbers a, b, and c separated by space.
+Output:
+Print "YES"(without quotes) if these sides can form a valid triangle, otherwise print "NO" (without quotes).
+
+Constraints
+0≤a,b,c≤180
+Sample Input 1:
+20 40 120
+Sample Output 1:
+YES
+Sample Input 2:
+100 18 42
+Sample Output 2:
+NO
+EXPLANATION:
+In the first example, angles set (20, 40, 120) can form a triangle with an area greater than 0.
+In the second example, angles set (100, 18, 42) will never form a valid triangle.

CodeChef DSA Learning series Solutions/Easy Problems to get started/Triangle With Angle/Solution.cpp

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+#include <iostream>
+using namespace std;
+
+int main() {
+
+    int a,b,c;
+    cin>>a>>b>>c;
+    if(a+b+c==180&& a>0 && b>0 && c>0){
+        cout<<"YES";
+    }
+    else{
+    cout<<"NO";
+    }
+    return 0;
+}

CodeChef DSA Learning series Solutions/Easy Problems to get started/Valid Triangle Or Not/README.md

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+You're given the length of three sides a, b, and c respectively. Now check if these three sides can form a triangle or not. Print "YES"(without quotes) if it can form a valid triangle with an area greater than 0, otherwise print "NO" (without quotes).
+
+Input:
+First-line will contain three numbers a, b, and c separated by space.
+Output:
+Print "YES"(without quotes) if these sides can form a valid triangle, otherwise print "NO" (without quotes).
+
+Constraints
+1≤a,b,c≤106
+Sample Input 1:
+2 4 3
+Sample Output 1:
+YES
+Sample Input 2:
+1 1 4
+Sample Output 2:
+NO
+EXPLANATION:
+In the first example, (2, 4, 3) can form a triangle with an area greater than 0.
+In the second example, (1, 1, 4) will never form a valid triangle.

CodeChef DSA Learning series Solutions/Easy Problems to get started/Valid Triangle Or Not/Solution.cpp

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+#include <iostream>
+using namespace std;
+
+int main()
+{
+    int a, b, c;
+    cin >> a >> b >> c;
+    if (a + b < c  a + c < b  b + c < a)
+        cout << "NO";
+    else
+        cout << "YES";
+    return 0;
+}