Prefill an Array.js

/* Create the function prefill that returns an array of n elements that all have the same value v. See if you can do this without using a loop.

You have to validate input:

v can be anything (primitive or otherwise)
if v is ommited, fill the array with undefined
if n is 0, return an empty array
if n is anything other than an integer or integer-formatted string (e.g. '123') that is >=0, throw a TypeError
When throwing a TypeError, the message should be n is invalid, where you replace n for the actual value passed to the function.

Code Examples

    prefill(3,1) --> [1,1,1]

    prefill(2,"abc") --> ['abc','abc']

    prefill("1", 1) --> [1]

    prefill(3, prefill(2,'2d'))
      --> [['2d','2d'],['2d','2d'],['2d','2d']]

    prefill("xyz", 1)
      --> throws TypeError with message "xyz is invalid" */

function prefill(n, v = undefined) {
  if (n === 0) return []
  if (parseInt(n) >= 0 && parseInt(n) == parseFloat(n))
    return new Array(parseInt(n)).fill(v)
  else throw new TypeError(`${n} is invalid`)
}

console.log(prefill(3, 1))
console.log(prefill(2, 'abc'))
console.log(prefill('1', 1))
console.log(prefill(3, prefill(2, '2d')))
console.log(prefill('xyz', 1))