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| 1 | +/** |
| 2 | + * 二叉树的增删查操作 |
| 3 | + */ |
| 4 | +export class TreeSearch { |
| 5 | + private root?: Node |
| 6 | + |
| 7 | + public find(data: number) { |
| 8 | + let p = this.root |
| 9 | + while (p != null) { |
| 10 | + if (data < p.data) { |
| 11 | + p = p.left |
| 12 | + } else if (data > p.data) { |
| 13 | + p = p.right |
| 14 | + } else { |
| 15 | + return p |
| 16 | + } |
| 17 | + } |
| 18 | + return p |
| 19 | + } |
| 20 | + |
| 21 | + public insert(data: number) { |
| 22 | + if (this.root == null) { |
| 23 | + this.root = new Node(data) |
| 24 | + return |
| 25 | + } |
| 26 | + let p = this.root |
| 27 | + while (p != null) { |
| 28 | + if (data < p.data) { |
| 29 | + if (p.left == null) { |
| 30 | + p.left = new Node(data) |
| 31 | + return |
| 32 | + } else { |
| 33 | + p = p.left |
| 34 | + } |
| 35 | + } else { |
| 36 | + if (data > p.data) { |
| 37 | + if (p.right == null) { |
| 38 | + p.right = new Node(data) |
| 39 | + return |
| 40 | + } else { |
| 41 | + p = p.right |
| 42 | + } |
| 43 | + } |
| 44 | + } |
| 45 | + } |
| 46 | + } |
| 47 | + |
| 48 | + /** |
| 49 | + * 删除的时候分三种情况 |
| 50 | + * @param data |
| 51 | + */ |
| 52 | + public delete(data: number) { |
| 53 | + // 先把对应的元素找出来,并且为了删除,也得记录父节点的内存地址 |
| 54 | + // 包含了null或者undefined两种情况 |
| 55 | + if (this.root == null) return |
| 56 | + let p: Node | undefined = this.root |
| 57 | + let pp = this.root |
| 58 | + while (p != null && p.data !== data) { |
| 59 | + pp = p |
| 60 | + data > p.data ? p = p.right : p = p.left |
| 61 | + } |
| 62 | + // 没有找到要删除的元素 |
| 63 | + if (p == null) return |
| 64 | + // 要删除的元素有两个子节点,需要找到右子树的最小节点,然后赋值 |
| 65 | + if (p.left != null && p.right != null) { |
| 66 | + // 右子树的最小节点 |
| 67 | + let minP = p.right |
| 68 | + // 右子树的最小节点的父节点 |
| 69 | + let minPP = p |
| 70 | + while (minP.left != null) { |
| 71 | + minPP = minP |
| 72 | + minP = minP.left |
| 73 | + } |
| 74 | + p.data = minP.data |
| 75 | + p = minP |
| 76 | + pp = minPP |
| 77 | + } |
| 78 | + |
| 79 | + // 有一个子节点或者没有子节点 |
| 80 | + let child |
| 81 | + if (p.left != null) { |
| 82 | + child = p.left |
| 83 | + } else if (p.right != null) { |
| 84 | + child = p.right |
| 85 | + } else { |
| 86 | + child = null |
| 87 | + } |
| 88 | + if (pp == null) { |
| 89 | + this.root = undefined |
| 90 | + } else if (pp.left === p) { |
| 91 | + pp.left = child! |
| 92 | + } else { |
| 93 | + pp.right = child! |
| 94 | + } |
| 95 | + } |
| 96 | + |
| 97 | + public printAllData(): void { |
| 98 | + this.printAll(this.root) |
| 99 | + } |
| 100 | + |
| 101 | + private printAll(node?: Node): void { |
| 102 | + if (node == null) return |
| 103 | + console.log(node.data) |
| 104 | + this.printAll(node.left) |
| 105 | + this.printAll(node.right) |
| 106 | + } |
| 107 | +} |
| 108 | + |
| 109 | +export class Node { |
| 110 | + data: number |
| 111 | + left?: Node |
| 112 | + right?: Node |
| 113 | + |
| 114 | + constructor(data: number) { |
| 115 | + this.data = data |
| 116 | + } |
| 117 | +} |
| 118 | + |
| 119 | +const treeSearch = new TreeSearch() |
| 120 | +treeSearch.insert(1) |
| 121 | +treeSearch.insert(4) |
| 122 | +treeSearch.insert(3) |
| 123 | +treeSearch.insert(2) |
| 124 | +treeSearch.insert(5) |
| 125 | +treeSearch.insert(0) |
| 126 | + |
| 127 | +treeSearch.delete(4) |
| 128 | + |
| 129 | +treeSearch.printAllData() |
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