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…tters in hand are included in the word
…rray to iterate through them and added upcase
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AdagramsWhat We're Looking For
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| def draw_letters() | ||
| letter_bag = ["A", "A", "A", "A", "A", "A", "A", "A", "A", "B", "B", "C", "C", "D", "D", "D", "D", "E", "E", "E", "E", "E", "E", "E", "E", "E", "E", "E", "E", "F", "F", "G", "G", "G", "H", "H", "I", "I", "I", "I", "I", "I", "I", "I", "I", "J", "K", "L", "L", "L", "L", "M", "M", "N", "N", "N", "N", "N", "N", "O", "O", "O", "O", "O", "O", "O", "O", "P", "P", "Q", "R", "R", "R", "R", "R", "R", "S", "S", "S", "S", "T", "T", "T", "T", "T", "T", "U", "U", "U", "U", "V", "V", "W", "W", "X", "Y", "Y", "Z"] | ||
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| # randomly selects the letters |
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This data structure makes sense for storing the pool of letters. However, laid out on one line like this it's not easy to see the distribution of letters. Something like this might be a bit easier to read:
letters = [
"A", "A", "A", "A", "A", "A", "A", "A", "A",
"B", "B",
"C", "C",
...
]Or, if you were feeling fancy:
letter_distribution = {
A: 9,
B: 2,
C: 2,
...
}
letters = []
letter_distribution.each do |letter, count|
count.times do
letters << letter
end
end| def uses_available_letters?(input, letters_in_hand) | ||
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| # takes word and puts it into an array | ||
| adagram = input.split(//) |
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There are two problems with this implementation:
-
You will never return
truefor a word with a repeated letter. For example,hand = ["E", "F", "R", "A", "E", "L", "V", "A", "D", "K"] uses_available_letters?("ADA", hand) # => false
The reason why is that Ruby's
Array#deletemethod will remove all matching elements from an array, not just the first match. -
This method is destructive! Because you call
deleteon the input, the hand will be reduced by the letters in the input. For example:hand = draw_letters puts hand # => ["T", "T", "E", "F", "R", "A", "E", "L", "V", "A"] uses_available_letters?('tte', hand) puts hand # => ["E", "F", "R", "A", "E", "L", "V", "A"]
This is bad because it's unexpected behavior. Nothing about "check whether this word is made up of letters in this hand" suggests that the hand will be changed in the process, but that's exactly what happens.
The way to address this problem would be to make a copy of the hand before removing letters from it.
I will acknowledge that none of the tests checked for either of these behaviors, but that doesn't change the fact that they're bugs.
| score_chart = | ||
| { | ||
| "A" => 1, "E" => 1, "I" => 1, "O" => 1, "U" => 1, "L" => 1, "N" => 1, "R" => 1, "S" => 1, "T" => 1, "D" => 2, "G" => 2, "B" => 3, "C" => 3, "M" => 3, "P" => 3, "F" => 4, "H" => 4, "V" => 4, "W" => 4, "Y" => 4, "K" => 5, "J" => 8, "X" => 8, "Q" => 10, "Z" => 10 | ||
| } |
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Again, this data structure feels like a good fit here, but I think it would be more readable if you were to split it across multiple lines.
| # highest score | ||
| words_with_scores.each do |word, score| | ||
| if score == words_with_scores.values.max | ||
| best_word = Hash.new |
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This works! However!
On line 77, you're calling values.max inside an each loop. That means you're doing the work of finding the max value (O(n)) once for each word (n times), for a total time complexity of O(n^2). We can improve this to O(n) by moving the max outside the loop:
max_score = words_with_scores.values.max
words_with_scores.each do |word, score|
if score == max_score
# ...| @@ -0,0 +1,117 @@ | |||
| # chooses 10 letters randomly from the letter bag | |||
| def draw_letters() | |||
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You have included the same file twice, as adagrams.rb and lib/adagrams.rb. Probably only the lib one should be included here.
Adagrams
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Comprehension Questions
Enumerablemixin? If so, where and why was it helpful?