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AdagramsWhat We're Looking For
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CheezItMan
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Mar 1, 2019
| require "csv" | ||
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| def draw_letters | ||
| alphabet = ["a", "a", "a", "a", "a", "a", "a", "a", "a", "b", "b", "c", "c", "d", "d", "d", "d", "e", "e", "e", "e", "e", "e", "e", "e", "e", "e", "e", "e", "f", "f", "g", "g", "g", "h", "h", "i", "i", "i", "i", "i", "i", "i", "i", "i", "j", "k", "l", "l", "l", "l", "m", "m", "n", "n", "n", "n", "n", "n", "o", "o", "o", "o", "o", "o", "o", "o", "p", "p", "q", "r", "r", "r", "r", "r", "r", "s", "s", "s", "s", "t", "t", "t", "t", "t", "t", "u", "u", "u", "u", "v", "v", "w", "w", "x", "y", "y", "z"] |
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Interesting choice in data structure for the available letters. It definitely works. Can you think of a concise way to do it?
| split_word.each do |l| | ||
| index = letters_in_hand.index(l) | ||
| if letters_in_hand.index(l) != nil | ||
| letters_in_hand.delete_at(index) |
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Just a note, that this method is destructive to the letters_in_hand array. So this could result in side effects if you checked to see if multiple words used the letters in hand.
| end | ||
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| def score_word(word) | ||
| letters_values = { |
| return best_word | ||
| end | ||
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| def is_in_english_dict?(input) |
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Nice work getting started with this.
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Adagrams
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Comprehension Questions
Enumerablemixin? If so, where and why was it helpful?