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| Original file line number | Diff line number | Diff line change |
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| @@ -1,8 +1,18 @@ | ||
| from heaps.min_heap import MinHeap | ||
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| def heap_sort(list): | ||
| def heap_sort(arr): | ||
| """ This method uses a heap to sort an array. | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: o(n^2) | ||
| Space Complexity: o(1) | ||
| """ | ||
| pass | ||
| heap = MinHeap() | ||
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| for x in arr: | ||
| heap.add(x) # o(n) | o(1) | ||
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| i = 0 | ||
| while not heap.empty(): | ||
| arr[i] = heap.remove() | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👀 |
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| i += 1 | ||
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| return arr | ||
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@@ -19,18 +19,36 @@ def __init__(self): | |
| def add(self, key, value = None): | ||
| """ This method adds a HeapNode instance to the heap | ||
| If value == None the new node's value should be set to key | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: o(n) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ However space complexity is O(log n). See comment below ⬇️ |
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| Space Complexity: o(1) | ||
| """ | ||
| pass | ||
| if value == None: | ||
| value = key | ||
| node = HeapNode(key, value) | ||
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| self.store.append(node) | ||
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| index = len(self.store) -1 | ||
| while index != None and index != 0: | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Interesting to do this iteratively! Because you are halving the index with each call to |
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| index = self.heap_up(index) | ||
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| def remove(self): | ||
| """ This method removes and returns an element from the heap | ||
| maintaining the heap structure | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: o(n) | ||
| Space Complexity: o(1) | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Because of the recursive |
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| """ | ||
| pass | ||
| if len(self.store) == 0: | ||
| return | ||
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| self.swap(0, len(self.store) - 1) | ||
| root = self.store.pop().value | ||
| self.heap_down(0) | ||
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| return root | ||
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@@ -44,10 +62,10 @@ def __str__(self): | |
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| def empty(self): | ||
| """ This method returns true if the heap is empty | ||
| Time complexity: ? | ||
| Space complexity: ? | ||
| Time complexity: o(1) | ||
| Space complexity: o(0-1) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Space complexity would be O(1) |
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| """ | ||
| pass | ||
| return len(self.store) == 0 | ||
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| def heap_up(self, index): | ||
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@@ -57,18 +75,33 @@ def heap_up(self, index): | |
| property is reestablished. | ||
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| This could be **very** helpful for the add method. | ||
| Time complexity: ? | ||
| Space complexity: ? | ||
| Time complexity: o(1) | ||
| Space complexity: o(1) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Creative to use this in conjunction with iteration in your |
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| """ | ||
| pass | ||
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| if self.store[index].key < self.store[(index-1)//2].key: | ||
| self.swap((index-1)//2, index) | ||
| return (index-1)//2 | ||
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| def heap_down(self, index): | ||
| """ This helper method takes an index and | ||
| moves the corresponding element down the heap if it's | ||
| larger than either of its children and continues until | ||
| the heap property is reestablished. | ||
| """ | ||
| pass | ||
| left = index * 2 + 1 | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ |
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| right = index * 2 + 2 | ||
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| if left < len(self.store): | ||
| if right< len(self.store) and self.store[left].key >= self.store[right].key: | ||
| swap_for = right | ||
| else: | ||
| swap_for = left | ||
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| if self.store[index].key > self.store[swap_for].key: | ||
| self.swap(index, swap_for) | ||
| self.heap_down(swap_for) | ||
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| def swap(self, index_1, index_2): | ||
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There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
✨ However time complexity is actually O(n log n) because
removeandaddare O(log n) operations instead of O(n). Because you are creating a heap of size n, space complexity will be O(n)