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[do-heewan] WEEK 01 Solutions #1704
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f6e158e
Two Sum solved
Do-heewan 2206296
Contains Duplicate solved
Do-heewan 445d292
Two Sum solved
Do-heewan 99826d9
Contains Duplicate solved
Do-heewan 004be14
Top K Frequent
Do-heewan 596cce5
Top K Frequent solved
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,8 @@ | ||
class Solution: | ||
def containsDuplicate(self, nums: List[int]) -> bool: | ||
sets = set(nums) | ||
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if len(nums) != len(sets): | ||
return True | ||
return False | ||
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,15 @@ | ||
class Solution(object): | ||
def topKFrequent(self, nums, k): | ||
count = {} | ||
result = [] | ||
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for i in nums: | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. collections.Counter를 쓰면 더 간단히 처리 가능합니다 There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 넵 피드백 감사합니다 |
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if i not in count: | ||
count[i] = 1 | ||
else: | ||
count[i] += 1 | ||
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count = sorted(count.items(), key=lambda x : x[1], reverse=True) | ||
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return [item[0] for item in count[:k]] | ||
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,10 @@ | ||
class Solution(object): | ||
def twoSum(self, nums, target): | ||
result = [] | ||
for i in range(len(nums)-1): | ||
for j in range(i+1, len(nums)): | ||
if (nums[i] + nums[j] == target): | ||
result.append(i) | ||
result.append(j) | ||
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return result |
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변수명이 sets인 것은 피하는 것이 좋습니다. set은 Python 내장 타입이므로 혼동 위험이 있어요