Skip to content

Changed the proof of "Theorem: Minimum-norm solution" #36

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 1 commit into
base: master
Choose a base branch
from
Open
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion ip_function_spaces.md
Original file line number Diff line number Diff line change
Expand Up @@ -171,7 +171,7 @@ $$\widetilde{u} = K^\dagger f.$$
```{admonition} Proof
:class: dropdown

We know that for $f \in \mathcal{D}(K^\dagger)$ the minimum-norm solution $\widetilde{u} \in \mathcal{N}(K)^\perp$ exists and unique. Using the fact that $K\widetilde{u} = P_{\overline{\mathcal{R}(K)}}f$ (due to the \textit{mimimum-residual} solution property) and the M-R equations, we have $\widetilde{u} = (I - P_{\mathcal{N}}(K))\widetilde{u} = K^\dagger K\widetilde{u} = K^\dagger P_{\overline{\mathcal{R}(K)}}f = K^\dagger K K^\dagger f = K^\dagger f$.
We know that for $f \in \mathcal{D}(K^\dagger)$ the minimum-norm solution $\widetilde{u} \in \mathcal{N}(K)^\perp$ exists and unique. The result now follows by $K\widetilde{u} = P_{\overline{\mathcal{R}(K)}}f$ (so we have that $\widetilde{u}$ is a \texit{minimum residual} solution) and that $K^\dagger \widetilde{u} \in \mathcal{N}(K)^\perp$ (so it is a minimum norm solution by Theorem \textit{Existence and uniqueness of the minimum-residual, minimum-norm solution}).
```

When defining the the solution through the M-P pseudo-inverse, we have existence uniqueness of the minimum-norm to {eq}`minres`. However, we cannot expect stability in general. For this, we would need $K^{\dagger}$ to be continuous. To see this, consider noisy data $f^{\delta} = f + e$ with $\|e\|\leq \delta$. For stability of the solution we need to bound the difference between the corresponding solutions $\widetilde{u}$, $\widetilde{u}^\delta$:
Expand Down