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/** | ||
10. Regular Expression Matching | ||
Given an input string s and a pattern p, implement regular expression matching with support for '.' and '*' where: | ||
'.' Matches any single character. | ||
'*' Matches zero or more of the preceding element. | ||
The matching should cover the entire input string (not partial). | ||
Example 1: | ||
Input: s = "aa", p = "a" | ||
Output: false | ||
Explanation: "a" does not match the entire string "aa". | ||
Example 2: | ||
Input: s = "aa", p = "a*" | ||
Output: true | ||
Explanation: '*' means zero or more of the preceding element, 'a'. Therefore, by repeating 'a' once, it becomes "aa". | ||
Example 3: | ||
Input: s = "ab", p = ".*" | ||
Output: true | ||
Explanation: ".*" means "zero or more (*) of any character (.)". | ||
Constraints: | ||
1 <= s.length <= 20 | ||
1 <= p.length <= 20 | ||
s contains only lowercase English letters. | ||
p contains only lowercase English letters, '.', and '*'. | ||
It is guaranteed for each appearance of the character '*', there will be a previous valid character to match. | ||
*/ | ||
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||
/** | ||
* @param {string} s | ||
* @param {string} p | ||
* @return {boolean} | ||
*/ | ||
var isMatch = function (s, p) { | ||
if (p.length === 0) { | ||
return s.length === 0; | ||
} | ||
|
||
const isFirstMatched = s.length > 0 && (s[0] === p[0] || p[0] === "."); | ||
|
||
if (p.length >= 2 && p[1] === "*") { | ||
return ( | ||
isMatch(s, p.substring(2)) || | ||
(isFirstMatched && isMatch(s.substring(1), p)) | ||
); | ||
} else { | ||
return isFirstMatched && isMatch(s.substring(1), p.substring(1)); | ||
} | ||
}; |