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Review Summary
I am approving your solution as it correctly implements all the core requirements of the task. Your function successfully counts the occurrences of a letter in a case-insensitive manner and produces the correct output.
While your implementation using a for loop is perfectly functional, the task guidelines recommended a more concise approach. A more Pythonic solution would be to chain built-in string methods together. For instance, you could first convert the entire phrase to lowercase and then use the .count() method to find the number of occurrences in a single line. This is a powerful pattern in Python that you may find useful in the future.
Great job getting the logic right!
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Footnotes
| for char in phrase: | ||
| if char.lower() == letter.lower(): | ||
| counter += 1 |
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While this loop is functionally correct, the task guidelines recommend avoiding explicit loops. Python has powerful built-in string methods that can solve this problem in a single line. Can you think of how to combine a method for case conversion with another for counting occurrences?
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