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Create aa.py #11

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21 changes: 21 additions & 0 deletions aa.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,21 @@
import sqlite3
from flask import Flask, request

app = Flask(__name__)

@app.route('/search')
def search():
# Get the user input from the query parameter
query = request.args.get('query', '')

# Vulnerable: User input is directly concatenated into the SQL query
connection = sqlite3.connect('example.db')
cursor = connection.cursor()
cursor.execute(f"SELECT * FROM users WHERE name = '{query}'") # SQL injection vulnerability

Check failure

Code scanning / CodeQL

SQL query built from user-controlled sources High

This SQL query depends on a
user-provided value
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.

Copilot Autofix

AI about 1 year ago

To fix the SQL injection vulnerability, we should use parameterized queries provided by the sqlite3 library. This approach ensures that user input is properly escaped and handled by the database driver, preventing SQL injection attacks.

  • Replace the f-string SQL query with a parameterized query.
  • Use placeholders (?) in the SQL query and pass the user input as a parameter to the execute method.
  • This change should be made in the search function in the aa.py file.
Suggested changeset 1
aa.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/aa.py b/aa.py
--- a/aa.py
+++ b/aa.py
@@ -13,3 +13,3 @@
     cursor = connection.cursor()
-    cursor.execute(f"SELECT * FROM users WHERE name = '{query}'")  # SQL injection vulnerability
+    cursor.execute("SELECT * FROM users WHERE name = ?", (query,))  # Use parameterized query to prevent SQL injection
     results = cursor.fetchall()
EOF
@@ -13,3 +13,3 @@
cursor = connection.cursor()
cursor.execute(f"SELECT * FROM users WHERE name = '{query}'") # SQL injection vulnerability
cursor.execute("SELECT * FROM users WHERE name = ?", (query,)) # Use parameterized query to prevent SQL injection
results = cursor.fetchall()
Copilot is powered by AI and may make mistakes. Always verify output.
results = cursor.fetchall()
connection.close()

return str(results)

if __name__ == '__main__':
app.run(debug=True)

Check failure

Code scanning / CodeQL

Flask app is run in debug mode High

A Flask app appears to be run in debug mode. This may allow an attacker to run arbitrary code through the debugger.

Copilot Autofix

AI about 1 year ago

To fix the problem, we need to ensure that the Flask application does not run in debug mode in a production environment. The best way to achieve this is to use an environment variable to control the debug mode. This way, we can enable debug mode during development and disable it in production without changing the code.

  1. Import the os module to access environment variables.
  2. Modify the app.run() method to set the debug parameter based on an environment variable.
Suggested changeset 1
aa.py

Autofix patch

Autofix patch
Run the following command in your local git repository to apply this patch
cat << 'EOF' | git apply
diff --git a/aa.py b/aa.py
--- a/aa.py
+++ b/aa.py
@@ -20,2 +20,4 @@
 if __name__ == '__main__':
-    app.run(debug=True)
+    import os
+    debug_mode = os.getenv('FLASK_DEBUG', 'False').lower() in ['true', '1', 't']
+    app.run(debug=debug_mode)
EOF
@@ -20,2 +20,4 @@
if __name__ == '__main__':
app.run(debug=True)
import os
debug_mode = os.getenv('FLASK_DEBUG', 'False').lower() in ['true', '1', 't']
app.run(debug=debug_mode)
Copilot is powered by AI and may make mistakes. Always verify output.