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  1. Correctness: The solution correctly implements the binary search for a rotated sorted array. The logic for determining whether the left or right half is sorted and adjusting the search range accordingly is accurate. The test cases provided also demonstrate the correctness of the solution.

  2. Time Complexity: The time complexity is O(log n), which is optimal for this problem. The student has correctly implemented the binary search algorithm.

  3. Space Complexity: The space complexity is O(1), which is optimal. No additional space is used beyond a few variables.

  4. Code Quality: The code is well-structured and readable. The use of comments to explain the logic is good practice. However, the variable names could be more descriptive (e.g., left and right could be low and high to match common conventions).

  5. Efficiency: The solution is efficient, but there is a minor issue in the calculation of mid. The student uses int mid = left + (right - left + 1) / 2;, which is slightly different from the standard int mid = left + (right - left) / 2;. While this does not affect the correctness in this case, it is better to stick to the standard formula to avoid potential off-by-one errors in other contexts.

  6. Test Cases: The student has provided good test cases, but it would be beneficial to include edge cases such as an empty array or an array with a single element.

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